20060606, 02:27  #1 
May 2004
2^{2}×79 Posts 
Fermat's Theoremtip of the iceberg?
For a glimpse of what lies beneath the tip you may visit
www.crorepatibaniye.com/failurefunctions and read the third conjecture.Tks to those taking the trouble. A.K.Devaraj 
20060607, 21:29  #2 
"Nancy"
Aug 2002
Alexandria
100110100011_{2} Posts 
You can rewrite as
For odd b, the right hand side is obviously ≡ 0 (mod m) as the lone c cancel. For even b, the term will be ≡ 2c (mod m). Alex 
20060616, 08:50  #3  
May 2004
2^{2}×79 Posts 
Quote:
the layered structure and to point out that Fermat's theorem is only the tip.In other words, we shd not be surprissed if a^(b^d^n + k*phi(phi(phi(m)))) + c is also congruent to 0 (mod m) subject to a^(b^d^n) + c being = m. A.K.Devaraj 

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