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#1 |
1A0E16 Posts |
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Hi. All this is pretty new to me and my maths is weak so forgive me if this is a daft question.
What are the chances that M39 (or one of the others) is the lower half of a twin prime? ie. M39 + 2 is also prime. Is it even possible? |
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#2 |
Aug 2002
A Dyson Sphere
32·7 Posts |
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I am not sure but i do not think that it is possible. I say this because we know that M39 is not divisible by 3 because it is prime. M39+1 is not divisible by 3 either because it is a power of 2. So M39+2 must be divisible by 3.
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#3 |
Banned
"Luigi"
Aug 2002
Team Italia
3·5·17·19 Posts |
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Uhm... a Mersenne Prime should be a string of binary "1" . If you add 2 (that is "10") to a Mersenne Prime the result won't give you a string of ones. That is, you won't get a Mersenne Prime anymore.
Luigi (where did I go wrong? :( ) |
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#4 | |
Banned
"Luigi"
Aug 2002
Team Italia
484510 Posts |
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![]() Next time I'll read the post and connect my brain before answering, sorry. Luigi |
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#5 | |
11111112 Posts |
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(Maybe I should have posted this in the maths forum. Sorry.) |
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#6 |
Sep 2002
22·3·5 Posts |
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powers of 2 are only divisible by 2 because 2 is its only prime factor. For example, 8 is 2x2x2. 16 is 2x2x2x2, etc.
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#7 |
Sep 2002
22·3·5 Posts |
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Also, I forgot to say that powers of any prime number are only divisible by that prime number, because it is its only prime factor. 81 = 3x3x3x3, 125 = 5x5x5, etc.
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#8 |
Aug 2002
Portland, OR USA
2×137 Posts |
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Maybe this has already been answered above and I got lost, but ...
What about the possibility of adjacent Mersennes (having Twin Primes as exponents) both being prime? examples: M(5), M(7) and M(17), M(19). So can there be more like that, or is there some relationship that prevents it? I guess a formal way to ask it would be: Can M(6k - 1) and M(6k + 1) both be prime for k > 3? |
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#9 |
P90 years forever!
Aug 2002
Yeehaw, FL
73×23 Posts |
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Mp could be the upper number in a twin prime. Will Edgington kept data on this at:
http://www.garlic.com/~wedgingt/M3status.txt It looks like no one has attacked M39 - 2 |
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#10 | |
Aug 2002
Rovereto (Italy)
100111112 Posts |
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eng. version: Hi Luigi! Could you explain why it happens? Thanks and regards! Guido |
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#11 | |
Banned
"Luigi"
Aug 2002
Team Italia
3·5·17·19 Posts |
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2^2 = 4 = 100b ---> 2^2 - 1 = 3 = 11b 2^3 = 8 = 1000b ---> 2^3 - 1 = 7 = 111b 2^5 = 32 = 100000b ---> 2^5 - 1 = 31 = 11111b 2^7 = 128 = 10000000 ---> 2^7 - 1 = 127 = 1111111b ... 2^n = 1(0)n b ---> 2^n - 1 = (1)n b (1)n means a string of n "1" Luigi |
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