A Curiosity

R.D. Silverman · 2012-05-10, 11:06

ECM found TWO separate factors of 11^235 - 10^235 in the same
night. A p52 and a p53.

1565984636408473301181204384728709597459123607625131

and

32802665957127969252215755918232198455522444479988271

The cofactor is prime.

Bob

Andi47 · 2012-05-10, 14:02

Nice!

Which B1 and B2 did you use?

R.D. Silverman · 2012-05-10, 14:29

Quote:

Originally Posted by Andi47

Nice!

Which B1 and B2 did you use?

B1 = 2 x 10^8. The default B2 for that B1. Both found in Step 2.

xilman · 2012-05-10, 18:40

Quote:

Originally Posted by R.D. Silverman

ECM found TWO separate factors of 11^235 - 10^235 in the same
night. A p52 and a p53.

1565984636408473301181204384728709597459123607625131

and

32802665957127969252215755918232198455522444479988271

The cofactor is prime.

Bob

Did you mail them to me? I'm on vacation this week and next with only poor access to email.

I'll update the tables when I get back.

Paul

(My current location is roughly 28N 18W. A few km north of Puerto Naos on La Palma to be a little more precise.)

R.D. Silverman · 2012-05-10, 20:00

Quote:

Originally Posted by xilman

Did you mail them to me? I'm on vacation this week and next with only poor access to email.

I'll update the tables when I get back.

Paul

(My current location is roughly 28N 18W. A few km north of Puerto Naos on La Palma to be a little more precise.)

Yes, I sent them.

2012-05-10, 11:06	#1
R.D. Silverman "Bob Silverman" Nov 2003 North of Boston 1D24₁₆ Posts	A Curiosity ECM found TWO separate factors of 11^235 - 10^235 in the same night. A p52 and a p53. 1565984636408473301181204384728709597459123607625131 and 32802665957127969252215755918232198455522444479988271 The cofactor is prime. Bob

2012-05-10, 14:02	#2
Andi47 Oct 2004 Austria 2482₁₀ Posts	Nice! Which B1 and B2 did you use? Last fiddled with by Andi47 on 2012-05-10 at 14:02

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