20180601, 17:51  #89 
Nov 2016
2764_{10} Posts 
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20180601, 17:54  #90 
Nov 2016
2^{2}·691 Posts 
Extended to n=512, since the smallest number such that the program cannot compute the full fraction is n=526. (see http://oeis.org/A003285 for the period length, the period length for n=1 to n=64 are 0, 1, 2, 0, 1, 2, 4, 2, 0, 1, 2, 2, 5, 4, 2, 0, 1, 2, 6, 2, 6, 6, 4, 2, 0, 1, 2, 4, 5, 2, 8, 4, 4, 4, 2, 0, 1, 2, 2, 2, 3, 2, 10, 8, 6, 12, 4, 2, 0, 1, 2, 6, 5, 6, 4, 2, 6, 7, 6, 4, 11, 4, 2, 0)
Last fiddled with by sweety439 on 20180601 at 18:03 
20180601, 21:34  #91 
Nov 2016
2^{2}×691 Posts 
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20180601, 21:53  #92 
Nov 2016
2^{2}·691 Posts 
......

20180601, 22:45  #93 
Nov 2016
5314_{8} Posts 
Format:
[prime, period]: smallest base 
20180601, 23:31  #94 
Nov 2016
101011001100_{2} Posts 
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20180613, 17:41  #95 
Nov 2016
2^{2}·691 Posts 
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20180619, 19:21  #96 
Nov 2016
2764_{10} Posts 
Relative class number h of cyclotomic field Q(zeta_n) for n up to 256. (only n<=236 have been doublechecked, thus there may be error for n>236)

20180701, 13:05  #97 
Nov 2016
ACC_{16} Posts 
..

20180710, 23:14  #98 
Nov 2016
2^{2}×691 Posts 
search limit: 2048 for n<=133, 1024 for n>=134

20180711, 23:30  #99 
Nov 2016
ACC_{16} Posts 
range: 1<=k<=n2 (we do not include k=n1)
conjectures: 0 only for n = 1, 2, 3 1 only for n = 23, 52 2 only for n = 4, 5, 7, 11 3 only for n = 6, 19, 26, 40, 59, 97, 105, 247, 266 4 only for 8, 9, 10, 13, 14, 16, 22, 25, 37, 41, 54, 70, 76, 110, 119, 141, 142, 189 and for every r, there is an n such that a(k)>r for all k>n. Last fiddled with by sweety439 on 20180711 at 23:39 