![]() |
![]() |
#848 |
Nov 2016
22×691 Posts |
![]() |
![]() |
![]() |
![]() |
#849 | |
Nov 2016
22×691 Posts |
![]() Quote:
S16: see post #463, already at n=15K S38: reserved by Prime Grid's GFN primes search, already at n=2^24-1 S50: reserved by Prime Grid's GFN primes search, already at n=2^24-1 R10: reserved by http://www.worldofnumbers.com/em197.htm (case d=3, k=817) and https://www.rose-hulman.edu/~rickert/Compositeseq/ (case b=10, d=3, k=817), already at n=554789 R12: see post #664, already at n=21760 R32: reserved by CRUS (case R1024, k=29), already at n=500K R49: reserved by https://github.com/RaymondDevillers/primes (see the "left49" file) (case b=49 family R{G}), already at n=10K |
|
![]() |
![]() |
![]() |
#850 |
Nov 2016
1010110011002 Posts |
![]()
Conjecture 1 (the strong Sierpinski conjecture): For b>=2, k>=1, if there is an n such that:
(1) k*b^n is neither a perfect odd power (i.e. k*b^n is not of the form m^r with odd r>1) nor of the form 4*m^4. (2) gcd((k*b^n+1)/gcd(k+1,b-1),(b^(945*2^s)-1)/(b-1)) = 1 for all s, i.e. for all s, every prime factor of (k*b^n+1)/gcd(k+1,b-1) does not divide (b^(945*2^s)-1)/(b-1). (i.e. ord_p(b) is not of the form 2^r (r>=0 if p = 2 or p = 3, r>=1 if p>=5) or m*2^r (m divides 945, r>=0) for every prime factor p of (k*b^n+1)/gcd(k+1,b-1)). (3) this (k,b) pair is not the case: b = q^m, k = q^r, where q is not of the form t^s with odd s>1, and m and r have no common odd prime factor, and the exponent of highest power of 2 dividing r >= the exponent of highest power of 2 dividing m, and the equation 2^x = r (mod m) has no solution. (the first 6 Sierpinski bases with k's which are this case are 128, 2187, 16384, 32768, 78125 and 131072) Then there are infinitely many primes of the form (k*b^n+1)/gcd(k+1,b-1). Conjecture 2 (the strong Riesel conjecture): For b>=2, k>=1, if there is an n such that: (1) k*b^n is not a perfect power (i.e. k*b^n is not of the form m^r with r>1). (2) gcd((k*b^n-1)/gcd(k-1,b-1),(b^(945*2^s)-1)/(b-1)) = 1 for all s, i.e. for all s, every prime factor of (k*b^n-1)/gcd(k-1,b-1) does not divide (b^(945*2^s)-1)/(b-1). (i.e. ord_p(b) is not of the form 2^r (r>=0 if p = 2 or p = 3, r>=1 if p>=5) or m*2^r (m divides 945, r>=0) for every prime factor p of (k*b^n-1)/gcd(k-1,b-1)). Then there are infinitely many primes of the form (k*b^n-1)/gcd(k-1,b-1). |
![]() |
![]() |
![]() |
#851 |
Nov 2016
53148 Posts |
![]()
(33*27^7876+1)/2 is (probable) prime
the first 4 conjectures of S27 are all proven!!! reserve R57 Last fiddled with by sweety439 on 2020-07-03 at 10:07 |
![]() |
![]() |
![]() |
#852 |
Nov 2016
22×691 Posts |
![]()
(281*57^5610-1)/56 is (probable) prime
the first 4 conjectures of R57 are all proven!!! reserve R49 (the corresponding page only searched it to 10K, I double check it and reserve it for n>10K) Last fiddled with by sweety439 on 2020-07-03 at 13:48 |
![]() |
![]() |
![]() |
#853 |
Nov 2016
22·691 Posts |
![]()
k is Sierpinski number base b if....
Code:
k b 1 (none) 2 (no such b < 201446503145165177) 3 (no such b < 158503) 4 == 14 mod 15 5 == 11 mod 12 6 == 34 mod 35 7 == 5 mod 24 or == 11 mod 12 8 == 20 mod 21 or == 47, 83 mod 195 or == 467 mod 73815 or == 722 mod 1551615 9 == 19 mod 20 10 == 32 mod 33 11 == 5 mod 24 or == 14 mod 15 or == 19 mod 20 12 == 142 mod 143 or == 296, 901 mod 19019 or 562, 828, 900, 1166 mod 1729 or == 563 mod 250705 or == 597, 1143 mod 1885 13 == 20 mod 21 or == 27 mod 28 or == 132, 293 mod 595 14 == 38 mod 39 or == 64 mod 65 15 == 13 mod 14 but not == 1 mod 16 16 == 38, 47, 98, 242 mod 255 or == 50 mod 51 or == 84 mod 85 17 == 11 mod 12 or == 278, 302 mod 435 or == 283, 355, 367, 607, 907 mod 1638 or == 373, 445, 646, 718 mod 819 18 == 322 mod 323 or == 398, 512 mod 1235 19 == 11 mod 12 or == 14 mod 15 or == 29 mod 40 20 == 56 mod 57 or == 132 mod 133 21 == 43 mod 44 or == 54 mod 55 22 == 68 mod 69 or == 160 mod 161 23 (== 21 mod 22 but not == 1 mod 8) or == 32 mod 33 or == 41 mod 48 or == 83 mod 530 or == 182 mod 795 24 == 114 mod 115 25 == 38 mod 39 or == 51 mod 52 Last fiddled with by sweety439 on 2020-07-04 at 15:56 |
![]() |
![]() |
![]() |
#854 |
Nov 2016
22·691 Posts |
![]() |
![]() |
![]() |
![]() |
#855 | |
Nov 2016
22·691 Posts |
![]() Quote:
Last fiddled with by sweety439 on 2020-07-04 at 13:54 |
|
![]() |
![]() |
![]() |
#856 |
Nov 2016
22·691 Posts |
![]()
Special cases of (k*b^n+-1)/gcd(k+-1,b-1) (+ for Sierpinski, - for Riesel):
* gcd(k+-1,b-1) (+ for Sierpinski, - for Riesel) = 1: the same as the original Sierpinski/Riesel problem in CRUS * Riesel case k=1: the smallest generalized repunit prime base b (see A084740 and http://www.fermatquotient.com/PrimSerien/GenRepu.txt) * Riesel case k=b-1: the smallest Williams prime base (b-1) * Sierpinski case k=1 and b even: the smallest generalized Fermat prime base b (see http://www.noprimeleftbehind.net/crus/GFN-primes.htm and http://jeppesn.dk/generalized-fermat.html) * Sierpinski case k=1 and b odd: the smallest generalized half Fermat prime base b (see http://www.fermatquotient.com/PrimSerien/GenFermOdd.txt) Last fiddled with by sweety439 on 2020-07-04 at 15:18 |
![]() |
![]() |
![]() |
#857 |
Nov 2016
ACC16 Posts |
![]()
we allow n=1 or n=2 or n=3 or n=4 or ..., but not allow n=0 or n=-1 or n=-2 or n=-3 or ... for (k*b^n+-1)/gcd(k+-1,b-1)
|
![]() |
![]() |
![]() |
#858 |
Nov 2016
1010110011002 Posts |
![]()
k is Riesel number base b if....
Code:
k b 1 (none) 2 (none) 3 (none) 4 == 14 mod 15 5 == 11 mod 12 6 == 34 mod 35 7 == 11 mod 12 8 == 20 mod 21 or == 83, 307 mod 455 9 == 19 mod 20 or == 29 mod 40 10 == 32 mod 33 11 == 14 mod 15 or == 19 mod 20 12 == 142 mod 143 or == 307 mod 1595 or == 901 mod 19019 13 == 5 mod 24 or == 20 mod 21 or == 27 mod 28 or == 38, 47 mod 255 14 == 8, 47, 83, 122 mod 195 or == 38 mod 39 or == 64 mod 65 15 == 27 mod 28 16 == 50 mod 51 or == 84 mod 85 Last fiddled with by sweety439 on 2020-07-06 at 02:34 |
![]() |
![]() |
![]() |
Thread Tools | |
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
The dual Sierpinski/Riesel problem | sweety439 | sweety439 | 13 | 2020-12-23 23:56 |
Semiprime and n-almost prime candidate for the k's with algebra for the Sierpinski/Riesel problem | sweety439 | sweety439 | 11 | 2020-09-23 01:42 |
The reverse Sierpinski/Riesel problem | sweety439 | sweety439 | 20 | 2020-07-03 17:22 |
Sierpinski/ Riesel bases 6 to 18 | robert44444uk | Conjectures 'R Us | 139 | 2007-12-17 05:17 |
Sierpinski/Riesel Base 10 | rogue | Conjectures 'R Us | 11 | 2007-12-17 05:08 |