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#1 |
Jul 2014
3×149 Posts |
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Will Eddington's page used to have a proof that
a prime divides only one prime-exponent composite Mersenne number. As far as I can tell there's no other proof of this anywhere on the web. His page has gone which is why I'm posting. Am I wrong? Last fiddled with by wildrabbitt on 2015-05-17 at 11:33 |
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#2 |
Jan 2005
6210 Posts |
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#3 |
Jul 2014
1BF16 Posts |
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It's a well known theorem.
Did you understand what I meant properly? e.g 23 * 89 = 2047 = (2^11) - 1 therefore 23 and 89 do not divide any other prime-exponent composite Mersenne. I've seen the proof, checked it too. |
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#4 |
Einyen
Dec 2003
Denmark
64038 Posts |
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It is discussed in this old thread: http://www.mersenneforum.org/showthread.php?t=16019
The proof for this statement is not given in the thread though. |
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#5 | |
"Forget I exist"
Jul 2009
Dumbassville
26·131 Posts |
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re-quoting from above:
Quote:
assume for example that b=2*a; we can show that 2*(2^a-1)+1 = 2^(a+1)-1 and we end up with a general formula of 2^(n+a)-1=2^n*(2^a-1)+(2^n-1) for the 2^n-1 (the part that isn't shown as a multiple of 2^a-1) to have a common factor with (2^a-1) a being the first exponent to have that factor means n must a multiple of a but if n is a multiple of a then n+a is also a multiple of a so only if the exponent b is a multiple of a will it have that factor in common since the primes are all relatively coprime it is shown that no ratio of the exponents fit this and the proof is done. edit: https://www.physicsforums.com/thread.../#post-3484943 Reference https://www.physicsforums.com/thread...inus-1.526047/ Last fiddled with by science_man_88 on 2015-05-17 at 15:24 |
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#6 |
∂2ω=0
Sep 2002
República de California
5·2,347 Posts |
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Is Will Eddington any relation to the late great astrophysicist Arthur, who famously organized the 1919 British solar-eclipse expedition which confirmed a key cornerstone of Einstein's general relativity theory?
Yes, I *know* it's not really a double-D (he said to the buxom lass). |
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