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 2020-08-02, 11:47 #1 Xyzzy     "Mike" Aug 2002 2×3×1,361 Posts August 2020
 2020-08-02, 17:11 #2 Dieter   Oct 2017 2×3×19 Posts For my understanding: „(0,1,2) is a losing position since the possible moves result in the positions (0,1,1) or (0,0,2)“ (0,1,2) can result in the position (0,0,1), too?
2020-08-03, 16:14   #3
tgan

Jul 2015

2·13 Posts

Quote:
 Originally Posted by Dieter For my understanding: „(0,1,2) is a losing position since the possible moves result in the positions (0,1,1) or (0,0,2)“ (0,1,2) can result in the position (0,0,1), too?
You are correct however (0,0,1) is also loosing

2020-08-29, 08:33   #4
LaurV
Romulan Interpreter

Jun 2011
Thailand

24E716 Posts

Quote:
 Originally Posted by Dieter (0,1,2) can result in the position (0,0,1), too?
Yes, in two ways, either taking one from last two stacks, or taking 2 from the last stake, which goes to (0,1,0), but for the purpose of the game, (0,0,1) and (0,1,0) are the same. Stacks are commutative.
However, as tgan said, that is also losing, so the (0,1,2) is losing, you can't force a win.
P.S. I see they fixed it, adding the (0,0,1) to the list.

Last fiddled with by LaurV on 2020-08-29 at 08:34

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