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#1 |
Jun 2012
Boulder, CO
6028 Posts |
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(2^15135397+1)/3 is a Fermat Probable prime! (4556209 decimal digits)
Also submitted to PRPTop. I am searching the range n=13M .. 17M currently, and nearly done. No other discoveries as of yet. |
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#2 |
Sep 2002
Database er0rr
2×3×691 Posts |
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#3 |
Sep 2006
The Netherlands
2×17×23 Posts |
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That's a very lucky find! Congrats on that one!
Had you asked me i would've guessed next one might've lurked at 30M earliest and 70M latest. |
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#4 |
Feb 2017
Nowhere
3×1,931 Posts |
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#5 |
Jun 2012
Boulder, CO
2×193 Posts |
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#6 | |
Feb 2017
Nowhere
3·1,931 Posts |
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Silly me, I failed to consider that you had tested multiple bases. ![]() Of course, these numbers automatically "pass" the test to base 2. Paper and pencil suffices for this one. If p > 3 is prime, N = (2^p + 1)/3, then (N-1)/2 = (2^(p-1) - 1)/3 is odd and divisible by p, so N = (2^p + 1)/3 divides 2^p + 1, and 2^p + 1 divides 2^((N-1)/2) + 1, so N divides 2^((N-1)/2) + 1. Now 2^((N-1)/2) + 1 divides 2^(N-1) - 1, so N divides 2^(N-1) -1, but does not divide 2^((N-1)/2) - 1. |
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#7 | |
"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·1,699 Posts |
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#8 | |
"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
339810 Posts |
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Last fiddled with by sweety439 on 2021-06-29 at 17:02 |
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#9 | |
Mar 2019
263 Posts |
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Maybe a mod can ban this guy until he stops flooding the forum with requests for other people to do things. |
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#10 | |
Sep 2002
Database er0rr
2·3·691 Posts |
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Last fiddled with by paulunderwood on 2021-06-29 at 20:38 |
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#11 |
"Curtis"
Feb 2005
Riverside, CA
2·5·232 Posts |
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We gave him some time off to consider his behavior, and it hasn't changed much. I suppose your suggestion and this reply might be considered yet another warning to Sweety before the banhammer falls again.
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