20100103, 08:28  #12 
Nov 2008
2×3^{3}×43 Posts 
Alpertron's applet can prove a 1xxxdigit number composite in a few seconds. Although there is a "Set prime" option in the DB (which not everyone has, and which is meant to be used on PRPs but has been maliciously used on composites), there is not a "Set composite" option.
Last fiddled with by 10metreh on 20100103 at 08:29 
20100104, 01:38  #13  
A Sunny Moo
Aug 2007
USA (GMT5)
6249_{10} Posts 
Quote:


20100104, 08:01  #14 
Nov 2008
2·3^{3}·43 Posts 
But it still takes ages to prove them prime (if they are prime), and above 1000 digits, it does MillerRabin instead of APRTCLE.

20100104, 08:12  #15  
Oct 2004
Austria
2·17·73 Posts 
Quote:
(According to Syd's email yesterday, he is currently too busy in RL, so he currently can't repair the work queue.) Last fiddled with by Andi47 on 20100104 at 08:14 

20100104, 16:39  #16  
A Sunny Moo
Aug 2007
USA (GMT5)
3·2,083 Posts 
Quote:


20100104, 16:45  #17 
Just call me Henry
"David"
Sep 2007
Cambridge (GMT/BST)
5822_{10} Posts 

20100329, 12:00  #18 
Mar 2004
Belgium
839 Posts 
Apperantely another factor was found
20100314 20:37:14 [XTBA>TSA] IvanleFou ElevenSmooth 24620+1 (B1 = 43000000) 35777343223943564685838560059604183163850304260261761 53 digits 
20101217, 20:02  #19 
May 2004
New York City
2^{3}·23^{2} Posts 
I sincerely suspect that Covering Sets are Titanically useful
in solving this problem. 
20130513, 22:01  #20 
"Carlos Pinho"
Oct 2011
Milton Keynes, UK
31·157 Posts 
[SGFC] hl found:
2^1575+1 http://factorization.ath.cx/index.php?query=2^1575%2B1 (B1 = 260000000) P58=4587197577871491467362503750976334015507261591370088644001 Last fiddled with by pinhodecarlos on 20130513 at 22:03 
20130514, 03:27  #21  
"William"
May 2003
New Haven
3×787 Posts 
Quote:
Which, unsurprisingly, finishes the entire 2^1575+1. Which finishes the entire 2^31501. 

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