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Old 2012-10-26, 08:02   #1992
jrk
 
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I've started polynomial selection.
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Old 2012-10-26, 08:08   #1993
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Quote:
Originally Posted by jrk View Post
I've started polynomial selection.
I can do the sieving and postprocessing again, I love this teamwork!

jfk, what do you use for poly selection?
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Old 2012-10-26, 09:43   #1994
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For polynomial selection, jrk uses (and contributes to) msieve.
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Old 2012-10-26, 12:06   #1995
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Quote:
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For polynomial selection, jrk uses (and contributes to) msieve.
I meant the hardware he uses.
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Old 2012-10-26, 12:16   #1996
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Quote:
Originally Posted by BigBrother View Post
I meant the hardware he uses.
Nvidia card.

Last fiddled with by pinhodecarlos on 2012-10-26 at 12:17
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Old 2012-10-27, 07:39   #1997
jrk
 
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Quote:
Originally Posted by BigBrother View Post
I can do the sieving and postprocessing again, I love this teamwork!
Here's a poly:
Code:
# aq4788:5073
# sieve with gnfs-lasieve4I14e on -a side from Q=7M to 29M
n: 29712030350422056407764987099112246876809290443496977616436205075052415484201116636430793917656509571664421538011459411836589836444181684355772841911
# norm 2.618315e-14 alpha -6.295424 e 7.663e-12 rroots 5
skew: 1166080.80
c0:  23750490127131804180671875097430105
c1:  665524504274009633437655504074
c2:  502177263538284124971913
c3: -940909512238674179
c4: -306611097123
c5:  296100
Y0: -39838125003638225433615547286
Y1:  46716866412058447
rlim: 14000000
alim: 14000000
lpbr: 29
lpba: 29
mfbr: 58
mfba: 58
rlambda: 2.55
alambda: 2.55
Quote:
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jfk, what do you use for poly selection?
msieve on a GTX 570
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Old 2012-10-27, 11:33   #1998
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Quote:
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Here's a poly:
Thanks, I have started sieving.
Quote:
Originally Posted by jrk
msieve on a GTX 570
That's a bigger gun than mine :)
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Old 2012-11-09, 14:13   #1999
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Now at line 5078, I'm already sieving the c133.
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Old 2012-11-09, 14:47   #2000
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How does a 2^4 * 31 driver break?
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Old 2012-11-09, 15:50   #2001
LaurV
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Quote:
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How does a 2^4 * 31 driver break?
the easiest way is when you succeed to raise 31 at ^2
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Old 2012-11-09, 19:37   #2002
Dubslow
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Quote:
Originally Posted by LaurV View Post
the easiest way is when you succeed to raise 31 at ^2
Or any even power. Then the sequence is effectively class 4, which means it needs to the rest (besides 2^4*31^(2n)) needs to be a product of 4 primes or less, but that's not sufficient. (There are some restrictions on what each prime has to be mod 4 or mod 8 etc. Also, and other prime raised to an even power doesn't count against that 4.)
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