![]() |
![]() |
#1 |
May 2004
22×79 Posts |
![]()
Let a + ib be a Gaussian integer. Let p be a rational integer prime of shape 4m + 3. Then ((a + ib)^(p^2-1) - 1) == 0 (mod p). This is subject to a + ib and p being co-prime.
|
![]() |
![]() |
![]() |
#2 |
Dec 2012
The Netherlands
24×101 Posts |
![]()
Yes, this follows from what we did on Gaussian integers in the discussion group (assuming I have understood you correctly).
Let \(R=\mathbb{Z}[i]/p\mathbb{Z}[i]\), the set of Gaussian integers modulo \(p\). Then \(R\) has \(p^2\) elements. As \(p\equiv 3\pmod{4}\), \(p\) remains prime in \(\mathbb{Z}[i]\) (see theorem 62) so \(R\) is a finite integral domain and hence a field, and therefore \(R^*\) has \(p^2-1\) elements. If \(a+bi\) and \(p\) are coprime then \(\overline{a+bi}\) is a unit in \(R\) so raising it to the power \(p^2-1\) gives \(\bar{1}\) by Lagrange's theorem (theorem 83). |
![]() |
![]() |
![]() |
#3 | |
May 2004
22·79 Posts |
![]() Quote:
|
|
![]() |
![]() |
![]() |
#4 |
Dec 2012
The Netherlands
161610 Posts |
![]() |
![]() |
![]() |
![]() |
#5 |
May 2004
1001111002 Posts |
![]()
Thank you very much. Would be glad if you wouldlet me have your full name; my id: dkandadai@gmail.com. Incidentally, as founder of maths corner on fb let me invite you to join that group.
|
![]() |
![]() |
![]() |
#6 |
"Brian"
Jul 2007
The Netherlands
7·467 Posts |
![]()
@devarajkandadai
Nick goes strictly by first name only, being the privacy-enthusiast that he is. You won't catch him on Facebook. And he's also too polite to mention that this result would be a simple observation for undergraduate students, so mentioning him by name in that context is not really necessary. ![]() |
![]() |
![]() |
![]() |
Thread Tools | |
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
Gaussian Aliquot Sequences? How to run in Pari/GP? | Stargate38 | Aliquot Sequences | 40 | 2019-11-30 11:14 |
Conjecture pertaining to modified Fermat's theorem | devarajkandadai | Number Theory Discussion Group | 12 | 2017-12-25 05:43 |
Gaussian integers- use of norms | devarajkandadai | Number Theory Discussion Group | 11 | 2017-10-28 20:58 |
Basic Number Theory 10: complex numbers and Gaussian integers | Nick | Number Theory Discussion Group | 8 | 2016-12-07 01:16 |
Gaussian Elimination Animation | Sam Kennedy | Programming | 3 | 2012-12-16 08:38 |