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Old 2018-05-06, 19:21   #1
wflaherty99
 
May 2018

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Smile Chalkdust crossnumber 07

If anyone could give solutions to some of these problems, that would be much appreciated!


http://chalkdustmagazine.com/categor...s/crossnumber/
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Old 2018-05-11, 11:42   #2
lavalamp
 
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Here are some answers or possible answers:

2 & 11:
Code:
153
370
371
407
4 & 5: 136 <--> 244

7:
Code:
378
666
990
24:
Code:
1634
8208
9474
26: 736

29:
Code:
54748
92727
93084
Edit: No leading zeroes.

Last fiddled with by lavalamp on 2018-05-11 at 12:23
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Old 2018-05-11, 14:24   #3
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13: 426
8: 426^6 = 5976646846618176
12: 426^5 = 14029687433376

17: 224

22: 427 - 630
10: 427^5 - 630^5
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Old 2018-05-12, 15:52   #4
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I've submitted my answer now.

For anyone looking to compare answers, the MD5 hash for the sum of my accross clues is e8938a2d47a3f3c420478335278eb2e9.

Another interesting point is that the answer is a semiprime equal to 5 * p16.
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Old 2018-05-14, 23:17   #5
petrw1
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My answer matches your 5XP16

For MD5....I tried 3 different MD5 generators and got 3 different answers but 1 matched yours.

I think we match!!!

I have to acknowledge that my son helped a ton and had the "BIG" calculator.
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Old 2018-05-15, 06:20   #6
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Quote:
Originally Posted by petrw1 View Post
I have to acknowledge that my son helped a ton and had the "BIG" calculator.
What's the "BIG" calculator? I used pari/gp for a few answers, is that what you mean?
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Old 2018-05-15, 09:28   #7
retina
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Quote:
Originally Posted by lavalamp View Post
... the MD5 hash is ... e8938a2d47a3f3c420478335278eb2e9.

... the answer is a semiprime equal to 5 * p16.
So all I have to do is hash all 16 and 17 digit numbers of the form 5*p16 and I can get the answer. Should be a doddle. brb

There are only 249,393,770,611,256 p16 numbers. Easy.

Last fiddled with by retina on 2018-05-15 at 09:35
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Old 2018-05-15, 15:15   #8
petrw1
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Quote:
Originally Posted by lavalamp View Post
What's the "BIG" calculator? I used pari/gp for a few answers, is that what you mean?
Java with BigInteger.
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Old 2018-05-15, 18:29   #9
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Quote:
Originally Posted by petrw1 View Post
Java with BigInteger.
Ah, no need for that. All of these fit well inside a 64 bit int, you can get 19 digits in those.

Quote:
Originally Posted by retina View Post
So all I have to do is hash all 16 and 17 digit numbers of the form 5*p16 and I can get the answer. Should be a doddle. brb

There are only 249,393,770,611,256 p16 numbers. Easy.
Sadly do-able these days in a couple of hours with a 1080 Ti.
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Old 2018-05-15, 20:12   #10
petrw1
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Quote:
Originally Posted by lavalamp View Post
Ah, no need for that. All of these fit well inside a 64 bit int, you can get 19 digits in those.
Yes, he mentioned that after he was done.
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