20110924, 03:40  #12  
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
1000010101011_{2} Posts 
Quote:
All primes congruent to 1 mod 3 must be raised to All primes congruent to 2 mod 3 must be raised to an even power Quote:
Last fiddled with by MiniGeek on 20111231 at 03:15 

20110924, 03:53  #13  
"Frank <^>"
Dec 2004
CDP Janesville
2·1,061 Posts 
Quote:


20110924, 04:06  #14 
"Frank <^>"
Dec 2004
CDP Janesville
100001001010_{2} Posts 
So does the exponent on the 3 matter? Also, does this change the sequences that get posted for work on this project? (Actually, at the very least, it lets out sequences with 5 raised to an odd power, correct? That takes 71 more out of play right off the bat....)

20110924, 07:08  #15 
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
3·3,109 Posts 
Will take 183936, too.

20110924, 13:17  #16  
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
10AB_{16} Posts 
Quote:
Quote:
A little more on my methods and why "sigma(3^n) mod 3 is 1" is important: see the formula for calculating the sigma of a number. If the current line is divisible by 3, that means it is 0 mod 3. Once we have its sigma, the next line is sigma  lastLine. Working mod 3, that's sigma  0, or sigma. So for the next line to not be divisible by 3, sigma != 0 mod 3 must be true. The sigma is the product of a series of numbers, which are the sigmas of the prime factors, e.g. sigma(2^2*3)=sigma(2^2)*sigma(3). If none of these numbers multiplied together are 0 mod 3, (i.e. all are 1 and 1, or 1 and 2 if you prefer) then the sigma will not be 0 mod 3, and so the next line will not be 0 mod 3. I'm sure I'm stating trivialities for mathematicians, but considering I'm the first in this thread to mention how to lose the 3, it might be of some use for learning for everyone. Last fiddled with by MiniGeek on 20110924 at 13:26 

20110924, 13:55  #17 
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
17·251 Posts 

20110924, 14:23  #18 
Sep 2010
Portland, OR
174_{16} Posts 
I'll take 243402.

20110924, 15:20  #19  
"Frank <^>"
Dec 2004
CDP Janesville
2×1,061 Posts 
Quote:


20110925, 04:59  #21 
"Frank <^>"
Dec 2004
CDP Janesville
2×1,061 Posts 
Just by way of encouragement.....
Just to help motivate everyone, here is what the status of bchaffin's latest termination was in my last pull:
Code:
734184 850. sz 111 2^2 * 3^3 * 83 PS. Check out the slope on that first downdriver run! Last fiddled with by schickel on 20110925 at 05:01 Reason: Add PS. 
20110925, 05:04  #22 
"Frank <^>"
Dec 2004
CDP Janesville
100001001010_{2} Posts 

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