20201125, 16:00  #1 
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
13·349 Posts 
13x666=2020
In honor of UncWilly's New Math:
https://www.mersenneforum.org/showpo...postcount=1068 Find a formula using only 13 and 666 to get 2020. You can only use +. , x, /, ^, !, √ 1. Find an answer with the fewest numbers (not digits). 2. Find an answer with the same number of each; and the fewest. For example my first attempt uses 11 numbers. So its an answer for 1. but not for 2. 666+666+666+13+13(13+13)/13(666+666)/666. 
20201125, 16:30  #2 
"Viliam Furík"
Jul 2018
Martin, Slovakia
2^{4}·3·7 Posts 
13*13*1313*13(13+13+13+13+13+13+13+13)/13 = 2020

20201125, 16:33  #3 
"Viliam Furík"
Jul 2018
Martin, Slovakia
2^{4}·3·7 Posts 

20201125, 17:02  #4 
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
13·349 Posts 

20201125, 17:11  #5 
"Curtis"
Feb 2005
Riverside, CA
4629_{10} Posts 
In the spirit of the original formula, solutions should use both 13 and 666.

20201125, 17:19  #6 
May 2020
1A_{16} Posts 
Trivial improvement to the original solution  10 numbers
666+666+666(666+666+666+666)/666+13+13 
20201125, 17:39  #7 
Just call me Henry
"David"
Sep 2007
Cambridge (GMT/BST)
11·17·31 Posts 
Not much of a record but the first to use ^
(13+13+13+13)/13 + (13+13/13)*(1313/13)^((13+13)/13) 7 of each (666+666+666+666)/666 + (13+666/666)*(1313/13)^((13+13)/13) 
20201125, 18:51  #8 
Feb 2019
3^{4} Posts 
Trial and error got me down to 9 numbers:
2020 = 666+((13+13)/13)*(666+13(13+13)/13) Last fiddled with by matzetoni on 20201125 at 18:59 
20201125, 19:37  #9 
Aug 2020
2×3×19 Posts 

20201125, 19:48  #10 
Aug 2020
2·3·19 Posts 
((666+666)/666)**(13(13+13)/13)1313(666+666)/666
6 each. 
20201125, 19:52  #11  
Aug 2020
2×3×19 Posts 
** means ^——I was using python as my calculator, as many would have guessed it.
Written with ^, my answer would be Quote:


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