20210115, 05:40  #1 
Apr 2012
Brady
2×3^{3}×7 Posts 
MArt
..short for math and art.
Here is how excited you should be about this post.. https://www.youtube.com/watch?v=4a2ZQtvMhRg This is the reason behind the post: http://www.concinnitasproject.org/portfolio/ Perhaps these could be used as a "Rorschach" test. Last fiddled with by jwaltos on 20210115 at 05:41 
20210115, 10:54  #2 
Dec 2012
The Netherlands
7×239 Posts 
For anyone who hasn't seen it yet:
Proofs from The Book 
20210115, 15:09  #3  
Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
2×3^{2}×593 Posts 
Quote:
The basic idea is that F_n  2 = 2^2^n  1 = (2^2^(n1) +1) (2^2^(n1) 1) = F_{n1} * (F_{n1} 2) by the difference of squares factorization formula and noting that F_n is coprime to F_m when m != m. 

20210115, 15:37  #4  
Dec 2012
The Netherlands
7×239 Posts 
Quote:
And the 3rd one uses Mersenne numbers (for prime p, a prime factor of \(M_p\) is greater than p). 

20210115, 16:32  #5  
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
1219_{16} Posts 
Quote:


20210116, 05:52  #6 
Apr 2012
Brady
2·3^{3}·7 Posts 

20210116, 06:05  #7  
Apr 2012
Brady
2·3^{3}·7 Posts 
Quote:
There is more to this than meets the eye. Last fiddled with by jwaltos on 20210116 at 06:06 
