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 2020-09-15, 15:50 #12 paulunderwood     Sep 2002 Database er0rr 67158 Posts Code: Mod(10,107)^100000000000000000000000000000000000000000 Mod(34, 107) ## *** last result computed in 0 ms . It actually works by left-right binary exponentiation modulo n And since 107 is prime we can use Fermat's little theorem: Code: Mod(10,107)^(100000000000000000000000000000000000000000%106) Mod(34, 107) Or something even "bigger": Code: Mod(10,107)^(100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%106) Mod(4, 107) Last fiddled with by paulunderwood on 2020-09-15 at 16:06
2020-09-15, 16:06   #13
drmurat

"murat"
May 2020
turkey

7210 Posts

Quote:
 Originally Posted by paulunderwood Code: Mod(10,107)^100000000000000000000000000000000000000000 Mod(34, 107) ## *** last result computed in 0 ms . It actually works by left-right binary exponentiation modulo n And since 107 is prime we can use Fermat's little theorem: Code: Mod(10,107)^(100000000000000000000000000000000000000000%106) Mod(34, 107) Or simething even "bigger": Code: Mod(10,107)^(100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%106) Mod(4, 107)

Thanks

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