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Old 2007-04-21, 17:09   #1
mfgoode
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Question Simple Arithmetic!



Is this equation correct ?

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

Mally
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Old 2007-04-22, 04:31   #2
mfgoode
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Thumbs down Wrong local time!



Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later!

Something wrong with the software? The next post on has been put later than my post and hence given preference.

Mally

P.S. it has been immediately corrected during writing of this reply.

Last fiddled with by mfgoode on 2007-04-22 at 04:33
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Old 2007-04-22, 04:53   #3
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Quote:
Originally Posted by mfgoode View Post

Is this equation correct ?
2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?
Mally
It depends on what the "." and "*" mean (in regular expressions (regexp) the former represent an arbitrary character, in DOS command lines the latter represent an arbitrary sequence of characters ;
finally [ ] might be the "Gaussklammer"...
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Old 2007-04-22, 08:11   #4
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One side is sqrt(2) larger than the other. Is that supposed to be a puzzle or just something you don't understand?
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Old 2007-04-22, 11:06   #5
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Quote:
Originally Posted by mfgoode View Post


Is this equation correct ?

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

Mally


Yes it is.
If . and * mean multiplication, and sq, rt are variable.
2 x y (2/3) = x y 2 (2/3) ...

Last fiddled with by victor on 2007-04-22 at 11:06
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Old 2007-04-22, 11:26   #6
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If . and * are multiplication what is the meaning of the concatenation of the two in the first part of the first term : "2.*sq".

In the formula I see a lot of (intentional ?) inconsistencies : "2." versus "2*", "rt" versus "rt."

My first intention was asking what the ".", the "*" and "sq.rt" meant. But then I realised it could be the core of the riddle.
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Old 2007-04-22, 16:53   #7
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Quote:
Originally Posted by mfgoode View Post


Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later!

Something wrong with the software? The next post on has been put later than my post and hence given preference.

Mally

P.S. it has been immediately corrected during writing of this reply.
.
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Old 2007-04-23, 03:41   #8
mfgoode
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Arrow characters!

Quote:
Originally Posted by m_f_h View Post
It depends on what the "." and "*" mean (in regular expressions (regexp) the former represent an arbitrary character, in DOS command lines the latter represent an arbitrary sequence of characters ;
finally [ ] might be the "Gaussklammer"...
Sorry for the confusion.

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

means 2 multiplied by the square root of 2/3 = square root of 2 multiplied by 2/3. So in one side the 2 is outside the square root on the other 2 is inside the square root.

* is multiplication, []are brackets, Its not the Gaussklammer.
'.' is full stop.
It is not a riddle! Its just a maths curiosity which looks odd and that it is wrong but it is right.

Mally
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Old 2007-04-23, 03:46   #9
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Lightbulb Radio music!

Quote:
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.
I had my launchcast radio on, on 'My Station' and believe it or not that guy on the keyboard was actually keeping in time to it. Amazing!

Mally
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Old 2007-04-23, 05:26   #10
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so you're claiming that (2)( \sqrt{\frac{2}{3}}) = \sqrt{(2) (\frac{2}{3})}?


(2)( \sqrt{\frac{2}{3}}) = \sqrt{(4) (\frac{2}{3})} \neq \sqrt{(2) (\frac{2}{3})}
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Old 2007-04-23, 08:38   #11
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Cool



Yes.

The version you have given is totally wrong

Mally

Last fiddled with by mfgoode on 2007-04-23 at 08:41
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