mersenneforum.org GHZ-days calculation Q
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 2014-06-27, 16:16 #1 tcharron   Jan 2013 111002 Posts GHZ-days calculation Q Here are three recent TF results... Code: Exponent Result Received age Result GHz-Days 334455661 NF 2014-06-27 15:33 0.0 no factor from 2^68 to 2^69 0.1787 334455061 NF 2014-06-27 15:29 0.0 no factor from 2^67 to 2^68 0.0894 106292027 NF 2014-06-27 15:22 1.8 no factor from 2^67 to 2^68 0.2812 Why are the larger exponents getting less credit than the smallest one? Not sure why it might matter, but the larger ones were from an i7, and the smaller ones on an older xeon.
 2014-06-27, 16:25 #2 firejuggler     "Vincent" Apr 2010 Over the rainbow 3·5·179 Posts Factor of mersenne numbers are in the form of 2*k*p+1 P is the exponent, k is a *random* number Between 2^67 and 2^68, there is more (2* 106292027* k)+1 multiple than (2*334455061 *k)+1 so, there is more work, therefore more credit.
 2014-06-27, 16:27 #3 LaurV Romulan Interpreter     "name field" Jun 2011 Thailand 22·11·223 Posts Factors q of mersenne numbers m are of the form q=2kp+1, where m=2^p-1. Technically, if p is bigger, you have less candidates to test, between 2^x and 2^(x+1). Imagine you have to find prime numbers of the form 11*something+1, and 13*something+1, between 2^15 and 2^16. Which are more?
 2014-06-27, 17:50 #4 tcharron   Jan 2013 22×7 Posts Doh! Makes perfect sense...
 2014-06-27, 23:27 #5 swl551     Aug 2012 New Hampshire 14508 Posts Here is the formula for calculating TF GHZdz GHZdz=28.50624 * (Math.Pow(2, to - 47) - Math.Pow(2, from - 47)) / exp

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