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 2012-01-01, 18:41 #1 garambois     "Garambois Jean-Luc" Oct 2011 France 809 Posts An aliquot sequence with huge, huge, huge tracts of sand !!! Hello everybody, Christophe Clavier took up a challenge on my website www.aliquotes.com : He found an aliquot sequence that is growing at each iteration by a factor at least equal to k=10 on 13 iterations ! The terms have more than 1900 digits and the guide is very, very huge !!! Impossible to put this aliquot sequence on factordb... If you want to see those 13 terms, click here : http://www.aliquotes.com/k10_13.txt Jean-Luc
 2012-01-01, 20:05 #2 firejuggler     "Vincent" Apr 2010 Over the rainbow 54338 Posts Wow! Gratz to him... Now, onto the next challenge!
 2012-01-01, 23:05 #3 henryzz Just call me Henry     "David" Sep 2007 Liverpool (GMT/BST) 32×5×7×19 Posts This makes me wonder at a possible challenge. What is the driver with the largest power of two that someone can both lose and terminate?
2012-01-02, 00:26   #4
science_man_88

"Forget I exist"
Jul 2009
Dumbassville

26·131 Posts

Quote:
 Originally Posted by henryzz This makes me wonder at a possible challenge. What is the driver with the largest power of two that someone can both lose and terminate?
here's a idea try and mutate my ali/aligen scripts to figure out the driver backwards as well and maybe I can try. I'm surprised I even know kinda what a driver is.

Code:
aligen41(w,s)=for(z=w,s,print("\n //ends in "z);for(x=1,#ali(z),for(y=1,#ali(ali(z)[x]),print(factor(ali(ali(z)[x])[y])"->"factor(ali(z)[x])))))
easy enough to get from the aligen40 script.

Last fiddled with by science_man_88 on 2012-01-02 at 00:43

2012-01-02, 01:50   #5
kar_bon

Mar 2006
Germany

23·32·41 Posts

Quote:
 Originally Posted by garambois Impossible to put this aliquot sequence on factordb...
It is possible: see here (will take some time to load), currently at index 14 with a C136 left.

2012-01-02, 04:33   #6
schickel

"Frank <^>"
Dec 2004
CDP Janesville

212210 Posts

Quote:
 Originally Posted by kar_bon It is possible: see (will take some time to load), currently at index 14 with a C136 left.
Heh, I wondered why the seed number was factored already. Unfortunately, we can't download it as an .elf file. Can Aliqueit handle it? Anybody up for the c136?

Also, if you've read this note, this sequence will increase for the first 5092 lines, at a minimum. Of course, after that, the driver is going to be a bit of a headache to escape.

I've managed to coax the first 150 lines out of the DB; it's actually pretty easy, just feed it a 2 plus the big factor for each line and it figures things out pretty quick.

2012-01-02, 08:01   #7
garambois

"Garambois Jean-Luc"
Oct 2011
France

14518 Posts

Quote:
 Originally Posted by kar_bon It is possible: see here (will take some time to load), currently at index 14 with a C136 left.
How did you do to put this sequence on db ?
I tried, but it was not possible ?
You went on "Report results " and "Report factors" and you made a copy-paste ?
Because, I have other aliquot sequences from Chritophe Clavier to put on db...
Jean-Luc

2012-01-02, 09:02   #8
schickel

"Frank <^>"
Dec 2004
CDP Janesville

2·1,061 Posts

Quote:
 Originally Posted by garambois How did you do to put this sequence on db ? I tried, but it was not possible ? You went on "Report results " and "Report factors" and you made a copy-paste ? Because, I have other aliquot sequences from Chritophe Clavier to put on db... Jean-Luc
Jean-Luc,

Yes, to load a sequence into the DB, you can just paste the text file of the sequence into the "Report Results"->"Report Factors" box.

If you leave it set to "Autodetect", the DB will detect the composite and the factors on each line and enter them into the DB. When you query the seed number of the sequence, it will "realize" the factors for each line are available and build the sequence up as far as it knows factors for.

 2012-01-02, 09:18 #9 Andi_HB     Mar 2007 Germany 23×3×11 Posts I have uploadet the composite numbers from this sequence because it wondered me why this cant uploadet to the db. To upload the numbers i took the composite in the db under search http://factordb.com/index.php and click factorize! ;-) The number is in the db then and i have sumbmitted the known factors. Regards Andi_HB
 2012-01-02, 10:12 #10 Andi47     Oct 2004 Austria 2·17·73 Posts From the FactorDB, sequence 2^19936*(2^19937-1)*27: Code: 486 12075 2723122910...2<12075> = 2^19936 · 29^2 · 3477395904...7<69> · 4315424797...1<6002> 487 12075 2917400407...4<12075> = 2^19936 · 3^2 · 29 · 17460561103408083236887015504720307<35> · 68751191016059342858040063918001477<35> · 4315424797...1<6002> 488 12075 5801267476...6<12075> = 2^19936 · 3^2 · 109 · 389 · 433 · 3770502861...3<64> · 4315424797...1<6002> 489 12076 1119434242...4<12076> = 2^19936 · 3 · 41 · 25709153 · 3801794144...1<63> · 4315424797...1<6002> How on earth have these p6x's been found? edit: I guess they just reported the huge factor... Last fiddled with by schickel on 2012-01-02 at 10:46 Reason: keeping the mystery alive.....
2012-01-02, 10:16   #11
schickel

"Frank <^>"
Dec 2004
CDP Janesville

2×1,061 Posts

Quote:
 Originally Posted by Andi47 From the FactorDB, sequence 2^19936*(2^19937-1)*27: Code: Checked 486 12075 (show) 2723122910...2<12075> = 2^19936 · 29^2 · 3477395904...7<69> · 4315424797...1<6002> Checked 487 12075 (show) 2917400407...4<12075> = 2^19936 · 3^2 · 29 · 17460561103408083236887015504720307<35> · 68751191016059342858040063918001477<35> · 4315424797...1<6002> Checked 488 12075 (show) 5801267476...6<12075> = 2^19936 · 3^2 · 109 · 389 · 433 · 3770502861...3<64> · 4315424797...1<6002> Checked 489 12076 (show) 1119434242...4<12076> = 2^19936 · 3 · 41 · 25709153 · 3801794144...1<63> · 4315424797...1<6002>` How on earth have these p6x's been found?? Or is there any other method to find this factors?
Look at the last factor on each line: notice anything?

Last fiddled with by schickel on 2012-01-02 at 10:48 Reason: changed "," to ":"; better, no?

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