20181023, 04:54  #12  
May 2004
2^{2}·79 Posts 
Quote:
(to be continued). 

20181024, 04:47  #13  
May 2004
474_{8} Posts 
A tentative definition
Quote:
Let N be a squarefree composite number such that atleast two of its prime factors are inverses (mod P^k) where k is a natural number. Then N is a tortion free number of degree k. (P is a prime number less than the largest prime factor of N). Last fiddled with by devarajkandadai on 20181024 at 04:51 Reason: To make it clearer 

20181024, 05:51  #14  
May 2004
2^{2}×79 Posts 
A tentative definition
Quote:


20181024, 11:04  #15  
May 2004
2^{2}·79 Posts 
Quote:


20181024, 12:26  #16 
"Forget I exist"
Jul 2009
Dartmouth NS
2×3×23×61 Posts 

20181024, 13:45  #17 
"Forget I exist"
Jul 2009
Dartmouth NS
10000011100010_{2} Posts 

20181024, 20:34  #18  
Aug 2006
5,987 Posts 
Quote:


20181028, 05:39  #19 
May 2004
2^{2}·79 Posts 
A tentative definition
Time to define inverses of higher order: let x and y be such that xy+1 = a*p^k+1 where a is a constant belonging to N, k is a natural number and p is a prime number. Then x and y are inverses of degree k.

20181029, 12:33  #20 
May 2004
2^{2}×79 Posts 
A tentative definition

20181029, 14:41  #21 
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
3·7·479 Posts 
Hint: P=2, and P^k+1 is a semiprime.

20181029, 15:13  #22 
Feb 2017
Nowhere
14124_{8} Posts 

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