20030806, 08:59  #1 
"Mike"
Aug 2002
2^{3}·3·331 Posts 
Special whole numbers...
List a whole number... The next poster has to say what makes that whole number special, and then he or she has to list a new one... (Please be clever and please try not to cheat too much!)
Discussion about these numbers is encouraged, but keep the chain going! :) For example... 7 
20030806, 09:00  #2 
"Mike"
Aug 2002
17410_{8} Posts 
7 wonders of the ancient world...
50 
20030806, 10:07  #3 
Jul 2003
Wuerzburg, Germany
2^{3} Posts 
50 States in the USA...
21 
20030806, 10:29  #4 
Aug 2002
2×101 Posts 
21 Blackjack
6 
20030806, 11:32  #5 
"Sander"
Oct 2002
52.345322,5.52471
29·41 Posts 
6 the first perfect number
9 
20030806, 12:51  #6 
Banned
"Luigi"
Aug 2002
Team Italia
2^{3}·599 Posts 
9 first odd square.(after 1)
42 ;) 
20030806, 13:13  #7 
Aug 2002
11001000_{2} Posts 
42  Answer to the question of life, the universe, and everything.
101 
20030806, 13:20  #8 
Banned
"Luigi"
Aug 2002
Team Italia
2^{3}×599 Posts 
101  dalmatians :D
101  the first prime above 100 101  the 101th Fibonacci number in binary notation 601 
20030806, 21:09  #9  
∂^{2}ω=0
Sep 2002
República de California
2^{6}×181 Posts 
Quote:
Beginning with just the smallest known prime, 2, we add one, to get 3, which is also prime. 2*3 + 1 = 7, which is again prime. The product of 2, 3 and 7 is 42. A more interesting question is: will such a Euclidtype inductive sequence eventually yield ALL the primes? For instance, if we continue the particular sequence above, we get: 2*3*7 + 1 = 43, which is again prime. 2*3*7*43 + 1 = 1807 = 13*139. 2*3*7*13*43*139 + 1 = 3263443, which is prime. 2*3*7*13*43*139*3263443 + 1 = 10650056950807 = 547*607*1033*31051. It's pretty easy to show that the Euclid sequence starting with 2 and 3 never yields a number divisible by 5, so the answer to the above question is no. So we refine the question: is there *any* Euclid sequence starting with a finite number of primes which yields all the primes? Either that, or 42 is Luigi's age. :) 

20030807, 20:47  #10 
Cranksta Rap Ayatollah
Jul 2003
641 Posts 
601 is the 110th prime, the divisors of 110 (sans 110) add up to 106, which is 601 backwards
539 
20030807, 23:34  #11  
∂^{2}ω=0
Sep 2002
República de California
2^{6}×181 Posts 
Quote:
http://www.hmso.gov.uk/si/si1995/Uksi_19950539_en_1.htm Isn't Google great? :D 5171655946 

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