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#1 |
"Sam"
Nov 2016
2·163 Posts |
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Like in algebra, how would one solve for x and y in:
4xy = 1 mod 29 2xy^2 = 1 mod 29 Yeah, the solution is obvious and easy in this one, how about when adding or subtracting terms? x^2-6y = 1 mod 210 3y^2+10y+12x = 1 mod 210 Which one would seem easier to solve? For both of them, I would go for substitution algebraic method, since the only constant (of degree 0) we are dealing with here in both equations is 1. but I don't know any better. Any help, feedback, or similar equations are appreciated here. Thanks. ![]() Last fiddled with by carpetpool on 2017-02-05 at 03:12 |
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#2 |
Dec 2012
The Netherlands
2·7·113 Posts |
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We shall be looking at quadratic equations modulo n shortly in the Basic Number Theory series:
http://www.mersenneforum.org/forumdisplay.php?f=132 |
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#3 |
Aug 2006
135118 Posts |
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Working mod primes is easy since you have the field structure -- it's just like working over the reals, you can add, subtract, multiply, and divide. Mod prime powers you do much the same thing but then use Hensel lifting. Mod composites you can use the CRT to reduce to prime powers.
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