20101029, 16:47  #1 
Dec 2008
you know...around...
2^{2}·5·31 Posts 
I get 13% less primes than I expected:(
Suppose I have an integer of magnitude of about 10^{28}.
If this number has no factors less than 10^{4}, am I right in assuming that this leaves a chance of about log(10^{28})/(2*log(10^{4})) = 1:3.5, i.e. 28.57%, that this number will be prime? 
20101029, 17:17  #2  
Jun 2003
2×3^{2}×269 Posts 
Quote:
1.781 =e^gamma 

20101029, 17:31  #3 
Dec 2008
you know...around...
1001101100_{2} Posts 

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