20070109, 22:22  #1 
Jan 2005
479 Posts 
Sierpinski / Riesel  Base 22
Sierpinski / Riesel  Base 22
Conjectured Sierpinski at 6694 [5,23,97] Conjectured Riesel at Riesel 4461 [5,23,97] Pesky 17 k's include (now 13 to go) Sierpinski: 22 (cedricvonck) 484 (cedricvonck) 1611 (michaf tested upto 12000) 1908 (michaf tested upto 12000) 4233 (michaf tested upto 12000) 5128 (michaf tested upto 12000) 5659 (michaf tested upto 12000) 6462 (michaf tested upto 12000) Riesel: 1013 (michaf tested upto 12000) 2853 (michaf tested upto 12000) 3104 (michaf tested upto 12000) 3656 (michaf tested upto 12000) 4001 (michaf tested upto 12000) 22 and 484 are special cases; only nontrivials occur with n=2^m If a prime is found for 22 case, 484 is also eliminated (n is one lower in that case) (larger) primes found: 4118*22^123471 (michaf) 6234*22^16010+1 (michaf) 942*22^18359+1 (michaf) 5061*22^24048+1 (michaf) 22*22^n+1 / 484*22^n+1 status: Code:
below (512): proven composite with phrot (512) 22^512+1 has factor 115443366400367617 (1k) 22^1024+1 has factor 2095383775764481 (2k) 22^2048+1 has factor 65465822271579614082713282973697 (4k) 22^4096+1 has factor 40961 (8k) 22^8192+1 has factor 147457 (16k) 22^16384+1 has factor 2342241402881 (32k) 22^32768+1 has factor 65537 (64k) 22^65536+1 has factor 27918337 (128k) 22^131072+1 has factor 786433 (256k) 22^262144+1 has factor 29884417 (512k) 22^524288+1 has factor 93067411457 (1M) no factors upto 1607651162167705601 (also P1 stage 1 done with B1=100000 and 25 ECM curves, B1=1000, B2=100000) (2M) no factors upto 285159626880581633 (4M) no factors upto 556968483053633537 (8M) no factors upto 9221584136710389761 (stopping here) (16M) 22^16777216+1 has factor 189162539974657 (32M) 22^33554432+1 has factor 21096518178045953 (64M) no factor upto 9202942106325221377 (stopping here) (128M) 22^134217728+1 has factor 91268055041 (256M) 22^268435456+1 has factor 7368180622415626241 (512M) no factor upto 9187751282130026497 (stopping here) (1G) no factor upto 9159662798383349761 (stopping here) Last fiddled with by michaf on 20070129 at 22:45 
20070110, 07:24  #2 
Mar 2004
Belgium
34F_{16} Posts 
base 22
n = 22 tested to 144895

20070110, 16:27  #3 
May 2003
2×127 Posts 
Containing
<<< 22*22^511+1 is not prime. 22*22^2047+1 is not prime. 22*22^3583+1 is not prime. 22*22^6655+1 is not prime. >>> Are you sure you know what you're doing? Those are 22^n+1, which can only ever be prime if n=2^m for some n, namely generalised Fermat numbers. 
20070110, 18:55  #4  
Sep 2006
Germany
2·5·19 Posts 
Quote:
18 * 18^n+1 ? and if not, could you please try to explain it to me? (Yea, I'm trying to learn the math behind these projects ) 

20070110, 19:13  #5 
May 2003
2·127 Posts 
They are also just 18^n+1. Again, they can only be prime if n is a power of 2, and would be Generalised Fermat Numbers. Have a look at Yves Gallot's GFN page for more info.

20070110, 22:32  #6 
Jan 2005
479 Posts 
4118*22^123471 is prime
6234*22^16010+1 is prime tests now at 18000 
20070111, 05:43  #7 
Mar 2003
New Zealand
485_{16} Posts 
If you want to sieve the GFN's, srsieve should recognise them as such and use a faster method of sieving as long as only the terms of the form n=2^m+1 appear in the input file. If you start srsieve with the v option it will print a message something like `filtering for primes of the form (2^m)x+1' if it has recognised the sequence as GFN. (If there are nonGFN sequences in the sieve as well then it will still notice the GFN's, but most of the benefit will be lost).

20070111, 11:18  #8  
Mar 2004
Belgium
34F_{16} Posts 
Quote:
Code:
k*b^n1 with k fixed k = 22 b = 22 n from 2 to 1.000.000 

20070112, 19:23  #9 
Jan 2005
479 Posts 
942*22^18359+1 is prime
5061*22^24048+1 is prime 
20070113, 03:05  #10 
"Jason Goatcher"
Mar 2005
3×7×167 Posts 
In terms of 22^(2^m)+1, is it possible to figure the odds that at least one value of m will yield a prime for the equation? Since the numbers get big so quickly, I'm thinking it's possible this may be a Sierpinski number that may never be proven, or at least not within my lifetime.
Can anybody do the math and figure the chance that it would or wouldn't yield prime if every single m value could be figured at once for the above equation? Last fiddled with by jasong on 20070113 at 03:05 
20070113, 09:32  #11 
Jan 2005
737_{8} Posts 
The chances are quite slim I suspect,
but sieving can be done quite easily. I have started yesterday a sieve for the first 4 numbers left, and that one did 40Mp/sec (now only 3 left since a factor was found for 512k) It will reach the limit of srsieve in about 1 day. If some numbers are left, well... it's getting very hard to test them. I will start a sieve for the next 4 after the first one finishes; that sievespeed is significantly slower (About 7Mp/sec), but will finish in reasonable time too. After that, I think I will let it go. 
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