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#1 |
Dec 2011
22·32 Posts |
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Let m be a positive odd integer.
If 2m = 2 (mod. m(m-1)) then m is a prime. True or False? This is true for m = 3, 7, 19, 43, 127, 163, 379, 487, 883, 1459, 2647, 3079, 3943, 5419, 9199, 11827, 14407, 16759, 18523, 24967, 26407, 37339, 39367. These are all primes and there are no other values lessthan 40 003. Is it possible to prove the conjecture? |
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#2 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
1A4016 Posts |
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I have no idea if it is provable or not, but there are only two more solutions below 10^9:
42463, 71443 |
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#3 | |
"Forget I exist"
Jul 2009
Dartmouth NS
100000111011002 Posts |
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6 = 2 mod (9-3=6) which is false 14 = 2 mod (49-7=42) which is false 38 = 2 mod (361-19=342) which is false the main problem is that m(m-1) = m^2-m which is larger than 2m once m>3 so all m>3 fail this test. or at least that's my interpretation of it. I looked up your phrasing and found it on mathhelpforum.com and apparently it's 2^m not 2m as it reads here. Last fiddled with by science_man_88 on 2012-09-16 at 12:06 |
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#4 | |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
26×3×5×7 Posts |
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![]() There are indeed a lot more solutions for that up to 10^9. Here are the first few (all prime): 42463, 71443, 77659, 95923, 99079, 113779, 117307, 143263, 174763, 175447, 184843, 265483, 304039, 308827, 318403, 351919, 370387, 388963, 524287, 543607, 554527, 581743, 585847, 674083, 688087, 698923, ... Last fiddled with by retina on 2012-09-16 at 13:36 |
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#5 | |
"Forget I exist"
Jul 2009
Dartmouth NS
22×72×43 Posts |
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#6 | |
Dec 2011
448 Posts |
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#7 |
Einyen
Dec 2003
Denmark
23·431 Posts |
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nevermind, was not correct.
Last fiddled with by ATH on 2012-09-16 at 15:06 |
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#8 |
Dec 2011
22·32 Posts |
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If it is possible to prove the following conjecture then I can prove the existance of an infinite sequence of Mersenne primes and I can represent them as an algebraic expression. However, they are not representable as numbers.
Let m be a positive odd integer. If 2m = 2 (mod. m(m-1)) then m is a prime. True or False? This is true for m = 3, 7, 19, 43, 127, 163, 379, 487, 883, 1459, 2647, 3079, 3943, 5419, 9199, 11827, 14407, 16759, 18523, 24967, 26407, 37339, 39367, and these are all prime. I can find no composite integers for which the statement holds. Is it possible to prove the conjecture? Last fiddled with by Stan on 2012-09-16 at 15:09 Reason: Add icon |
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#9 |
"Forget I exist"
Jul 2009
Dartmouth NS
20EC16 Posts |
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see also:
http://mersenneforum.org/showthread.php?p=311833 http://mersenneforum.org/showthread.php?p=311851 and probably more. oh yeah I forgot I originally found it correctly on: http://mathhelpforum.com/number-theo...onjecture.html Last fiddled with by science_man_88 on 2012-09-16 at 15:31 |
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#10 | |
"Forget I exist"
Jul 2009
Dartmouth NS
100000111011002 Posts |
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Mm = 1 mod (m(m-1)) we know: Mm = 1 mod m, if m is prime so Mm would need the correct residue mod (m-1) for this to work. |
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#11 |
∂2ω=0
Sep 2002
República de California
5×2,351 Posts |
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Dude, did you really need to start 3 separate threads on this? I merged all of 'em here.
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