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#1 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
111110000002 Posts |
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* Planet-A has a population of 95 people.
* Pandemic-X is in the process of breaking out across the planet * An unknown number of individuals are infected by Virus-X * There is a shortage of Test-Kits and not everyone can be tested * Fluid samples from any number of individuals can be combined and tested per a single Test-Kit ** If any of the combining individual are infected the test will be positive else negative * What is the minimum number of Kits required to determine who is infected and who is not? *** Spoiler alert: I have no idea what the answer is, but I think this is a useful problem to figure out given the current affairs of the Planet-Earth Thank you for your time and insights. ETA I assume the answer would be a function of number/proportion of the infected individuals. Last fiddled with by a1call on 2020-02-26 at 04:30 |
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#2 | |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
22×72×31 Posts |
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This puzzle might be more interesting if you state in advance the number of infected people. Then you can devise a test plan to minimise the total number of tests. Last fiddled with by retina on 2020-02-26 at 04:57 |
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#3 |
Jun 2003
485610 Posts |
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#4 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
26·31 Posts |
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Brilliant indeed, thank you.
Good to know the algorithm is useful and already in use for the purpose. ETA not sure though if the algorithm was used in case of the Cruse ship off the coast of Japan for example. Last fiddled with by a1call on 2020-02-26 at 06:11 |
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#5 | |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
22·72·31 Posts |
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One way to approach this is to sample a small population first with individual tests to obtain an approximate percentage and then apply some statistical methods to reduce the number subsequent tests. This would require good unbiased selection criteria to start with. |
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#6 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
26×31 Posts |
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Something bothers me about that video. There is a logical symmetry/interchangable-ity between infected and non-infected individuals. If the algorithm requires n tests for say 20% infected then it should require exactly n tests for 100%-20%=80%. Shouldn't it?
Then the claim that above 30% infection rates will require more tests than number of individuals is false. Corrections are appreciated. |
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#7 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
26·31 Posts |
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Nevermind, I see my mistake. Out is not symmetrical.
Since 1 infection per batch will give positive but -1 infection per batch will not give negative result. Last fiddled with by a1call on 2020-02-26 at 10:53 |
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#8 | |
Jul 2009
Germany
54710 Posts |
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the unknown number of individuals are infected by Virus-X = 0. Just combine all fluid samples from the 95 people. In the case the unknown number of individuals are infected by Virus-X > 0. you need a minimum amount of 2 test-kits. In this case the first test is positive. With the second test kit you have to test the remaining 94 People. Number of Infections = 1. easy to extend to an algorithm.... Last fiddled with by moebius on 2020-02-28 at 07:57 Reason: erweiterte Lösung |
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#9 | |
"Rashid Naimi"
Oct 2015
Remote to Here/There
26×31 Posts |
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For reference purposes:
Quote:
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#10 |
Romulan Interpreter
Jun 2011
Thailand
100100001100012 Posts |
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Given the initial problem, 1000, 10%, we can do better! (even if you don't know the exact quantity of the poisoned glasses).
If you know there are exactly 100 glasses poisoned from 1000, you can do even better-better ![]() Last fiddled with by LaurV on 2020-04-03 at 09:52 |
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Thread | Thread Starter | Forum | Replies | Last Post |
Manic of a panic is geopolitical | a1call | Lounge | 1318 | 2021-02-19 03:10 |