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#23 |
"Ben"
Feb 2007
25×3×5×7 Posts |
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Could't resist one more - no parens are fun!
56 = 8 * 2 + 5 * 8 - 9/9 + 3/3 |
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#24 |
Jan 2016
Mighty Black Stump
1016 Posts |
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57 = 8 x 8 + 5 x 2 - 9 - 9 + 3/3
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#25 |
May 2009
Russia, Moscow
25·79 Posts |
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58 = 8 + 8 * 5 + 2 * 9 - 9 + 3/3
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#26 | |
Jun 2003
12EA16 Posts |
![]() Quote:
(9/9*3/3) (9/9+3/3) (9-9/3-3) ((9+9/3)/3) (9/9-3-3) (9-9+3+3) (9/9+3+3) (9-9/3/3) (9*9/3/3) (9+9/3/3) *DROPS MIC* ![]() |
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#27 |
Romulan Interpreter
Jun 2011
Thailand
23B016 Posts |
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Haha, now if we use only 8258 to make* 0, 10, 20, 30, +\(\infty\), then we are done...
If possible, only once, no parenthesis... *technically, as you posted 0 to 10 inclusive, we would only need to make 0, 11, 22, 33, 44... ![]() Last fiddled with by LaurV on 2019-01-10 at 08:58 |
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#28 |
Just call me Henry
"David"
Sep 2007
Cambridge (GMT/BST)
2·2,897 Posts |
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Actually they can be used to add or subtract 0 to 10 meaning a range of 21 not 11. Can this list be expanded? What can be done with just the last 3 digits?
59 = (8+2)*5+8 + (9/9*3/3) 60 = (8+2)*5+8 + (9/9+3/3) 61 = (8+2)*5+8 + (9-9/3-3) 62 = (8+2)*5+8 + ((9+9/3)/3) 63 = (8+2)*5+8 - (9/9-3-3) 64 = (8+2)*5+8 + (9-9+3+3) 65 = (8+2)*5+8 + (9/9+3+3) 66 = (8+2)*5+8 + (9-9/3/3) 67 = (8+2)*5+8 + (9*9/3/3) 68 = (8+2)*5+8 + (9+9/3/3) The 5 axn posted was actually -5. Fortunately I checked my results. It is so easy to make a mistake with this puzzle!! |
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#29 |
Jun 2003
2·32·269 Posts |
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#30 | |
Just call me Henry
"David"
Sep 2007
Cambridge (GMT/BST)
579410 Posts |
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![]() I might consolidate correct results in the first post at somepoint. I will probably also make a list for the last 4 digits to aid with creating more. Last fiddled with by henryzz on 2019-01-10 at 11:17 |
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#31 |
"Adolf"
Nov 2013
South Africa
61 Posts |
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69 = ((8 - 2 + 5 + 8 + (9/9) + 3)) * 3
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#32 |
Jun 2003
12EA16 Posts |
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#33 |
Jun 2003
2·32·269 Posts |
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