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#1 |
Oct 2008
n00bville
13408 Posts |
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As far as I know I just finished successfully the biggest LL test:
[Dec 29 18:02] M123456811 is not prime. Res64: A41D7D17044F74xx. We4: xxx [Dec 29 18:02] Setting affinity to run helper thread 1 on any logical CPU. .... [Comm thread Dec 29 18:02] pnErrorResult=0 [Comm thread Dec 29 18:02] CPU credit is 605.4956 GHz-days. [Comm thread Dec 29 18:02] ==END== Unfortunately it's not a prime number (it even looks very nice). It needed more than a year with two cores running. Anyway, who got more CPU credits? ;) Last fiddled with by akruppa on 2010-12-29 at 19:46 Reason: removed last 2 residue digits |
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#2 |
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
11·389 Posts |
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Not quite the biggest, these two beat it out:
http://www.mersenne.org/report_expon...p_lo=332197123 http://www.mersenne.org/report_expon...p_lo=150000091 By the way, here's a listing with a lot of information on exponent statuses: http://www.mersenne.org/primenet/ And here's a list of LL results for exponents over 100M: http://www.mersenne.org/report_LL/?e...B1=Get+LL+data Third-biggest, still quite impressive! Unfortunately, with a non-0 error code, this test is more likely (than average) to be bad. Please hide the last two hexdigits in the Res64 so nobody is able to resubmit that result and get all that credit without any work. By the way, I should hope you really did TF farther than the 65 bits and no P-1 that PrimeNet knows about before running this monster LL. The error code indicates 1 ROUNDOFF > 0.4 error occurred. From this thread, it looks like about 40% of numbers with that sort of error code are usually bad. Considering this and the length of time this number took, I'd give it a 50/50 chance for actually being correct. Last fiddled with by TimSorbet on 2010-12-29 at 18:03 |
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#3 |
Jul 2009
Germany
11·61 Posts |
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Unfortunatley it is a Suspect LL.
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#4 | |
Oct 2008
n00bville
10111000002 Posts |
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Tell me more about the correct way to proceed TF and P-1 (up to which bits?) before running such a number? I thought Prime95 will do the necessary (and useful) tests for itself? Any receipts? Last fiddled with by joblack on 2010-12-29 at 18:18 |
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#5 |
"Lucan"
Dec 2006
England
2·3·13·83 Posts |
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I think <2025 is pie in the sky.
David Last fiddled with by davieddy on 2010-12-29 at 18:31 |
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#6 | |
Oct 2008
n00bville
25·23 Posts |
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#7 |
"Lucan"
Dec 2006
England
194A16 Posts |
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#8 | |
"Richard B. Woods"
Aug 2002
Wisconsin USA
22·3·641 Posts |
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Test=aID,exponent,TFdone,P-1done where TFdone = bit level to which TF had previously been done and P-1done = 1 if P-1 has been done, else 0 If your worktodo line was: Test=xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx,123456811,73,1 for instance, then prime95 would think that it had already been TFed to 2^73 (which is the default limit for exponents from 115300000 to 147500000), and that standard P-1 had already been done. It should have looked like: Test=xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx,123456811,65,0 which indicates that no P-1 has been done, and TF to only 2^65, matching the PrimeNet database entry for that exponent. - - - (I'm tracking down what prime95 would do if the last two parameters had been left off.) Last fiddled with by cheesehead on 2010-12-29 at 20:13 |
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#9 |
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
122368 Posts |
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Exponent Status Data 123456811 No factors below 2^65 Suspect LL A41D7D17044F74__ by "joblack" on 2010-12-29 Assigned LL testing to "joblack" on 2010-12-07 <==================== History no factor from 2^62 to 2^63 by "GIMPS Visualization" on 2009-03-06 History no factor from 2^63 to 2^64 by "Richard" on 2010-05-30 History no factor from 2^64 to 2^65 by "Richard" on 2010-12-06 History A41D7D17044F74__ by "joblack" on 2010-12-29 |
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#10 | |
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
11×389 Posts |
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Looks like you might have forgot about this or can't do it right now, so I did it: it ("Test=123456811") is the same as if you told it no TF or P-1 had been done ("Test=123456811,0,0"), so it starts TFing at the beginning. This would duplicate a little work, but only about as much as the first bit level you need to test would take, (i.e. from 0 to 2^65 is roughly the same work as from 2^65 to 2^66, and you needed to do 2^65 to 2^73) a minuscule amount for a test this large. Last fiddled with by TimSorbet on 2010-12-29 at 23:35 |
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#11 |
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
1005910 Posts |
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If I remember correctly, read it sometime ago on this forum -- "if someone decides to finish the TF from 65 to 73 bits and finds a factor - the LL credit will be voided."
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