20200412, 22:10  #34  
Jan 2020
12_{10} Posts 
Quote:
According to your computations, after ten days the cities are contaminated ABOVE 100%. You noticed it, and you hid it with well placed if statements. But the main problem is that you are counting many infection events more than once. As an example, on day 2 the correct values should be (using your format): A = 10000, B = 1900, C = 1981, D = 1981, E = 199. Last fiddled with by 0scar on 20200412 at 22:19 Reason: Adding correct values on day 2 

20200413, 08:46  #35  
"Kebbaj Reda"
May 2018
Casablanca, Morocco
67_{8} Posts 
Quote:
Day 0 infection B: 0 Day 1 infection B: 1000 (10000 * 0.1) Day 2 infection B: 2000 (1000(day 1) + 10000 * 0.1 = 2000) Where did your 1900 come from for city B. Please answer with calculations. Last fiddled with by Kebbaj on 20200413 at 08:49 

20200413, 09:07  #36  
Jan 2020
2^{2}×3 Posts 
Quote:
1000+9000*0.1= 1900. Otherwise, some people infected on previous days are counted over and over again, quickly exceeding 100%. 

20200413, 10:19  #37 
"Kebbaj Reda"
May 2018
Casablanca, Morocco
110111_{2} Posts 
Yes your reason is better than mine. I had seen that the source city A with a high viral load of 10000 infected cases can count 1000 healthy cases in city B.

20200414, 16:40  #38  
Jan 2017
2·37 Posts 
Anyone have an idea what the newly added bonus thing means? It says:
Quote:


20200414, 17:30  #39  
Jan 2020
2^{2}·3 Posts 
Quote:
My guess: somewhere before day 81. 

20200427, 07:44  #40 
Oct 2017
89 Posts 
Are there many equivalent adjacency matrices with 70,0074873 % after 10 days or is my code wrong?

20200427, 08:21  #41 
Sep 2017
7×11 Posts 
Not sure, but there must be many equivalent matrices, at least the permutations of all the rest of the points except the originating city, minus the degenerate cases due to isomorphic connections. If the graph is dense, there will be many degenerate cases, but if the it is sparse, you will have little number of degenerate cases.

20200427, 16:30  #42 
Jul 2015
14_{10} Posts 
Yes i am getting this result also not sure if it is good enough

20200427, 18:31  #43  
"Hugo"
Jul 2019
Germany
31 Posts 
The optimum result of 70.007... for 10 days and 8 nodes corresponds to only one unlabeled connected graph. There are several ways to chose the root node in this graph all leading to the same probability of "all nodes infected". Since the updated description says
Quote:


20200427, 20:35  #44  
Oct 2017
89 Posts 
Quote:
Could that be „Konjunktiv“? We also would accept... (wir würden auch...akzeptieren)? A question for a native speaker! Last fiddled with by Dieter on 20200427 at 20:38 Reason: Complement 

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