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2010-11-10, 19:30   #34
CRGreathouse

Aug 2006

10111001001012 Posts

Quote:
 Originally Posted by science_man_88 I figured as much. nobody understands me.
Our problems are mathematically dual: You are rarely understood by anyone and I rarely understand anyone.

2010-11-10, 20:26   #35
science_man_88

"Forget I exist"
Jul 2009
Dumbassville

100000110000002 Posts

Quote:
 Originally Posted by CRGreathouse Our problems are mathematically dual: You are rarely understood by anyone and I rarely understand anyone.
maybe if i can figure out that think I thought of we can get both solved lol

2010-11-11, 01:32   #36
3.14159

May 2010
Prime hunting commission.

24·3·5·7 Posts

Quote:
 Originally Posted by CRGreathouse Our problems are mathematically dual: You are rarely understood by anyone and I rarely understand anyone.
Well, even if you make a serious attempt to understand what he posts, you might understand about 10% of what he posts.

2010-11-11, 04:22   #37
CRGreathouse

Aug 2006

3×52×79 Posts

Quote:
 Originally Posted by 3.14159 Well, even if you make a serious attempt to understand what he posts, you might understand about 10% of what he posts.
I'm amused by the ambiguity in the post.

2010-11-11, 04:42   #38
3.14159

May 2010
Prime hunting commission.

24×3×5×7 Posts

Quote:
 Originally Posted by CRGreathouse I'm amused by the ambiguity in the post.
Ambiguity? Where?

2010-11-11, 04:55   #39
CRGreathouse

Aug 2006

172516 Posts

Quote:
 Originally Posted by 3.14159 Ambiguity? Where?
The antecedents, of course -- you could easily reverse them.

Last fiddled with by CRGreathouse on 2010-11-11 at 05:10

 2010-11-12, 15:44 #40 science_man_88     "Forget I exist" Jul 2009 Dumbassville 26×131 Posts could we add sumdigits(sumdigits(x)+sundigits(y)) = sumdigits(x*y) into the first theory ? I think it works can anyone help prove it ?.
 2010-11-12, 19:43 #41 CRGreathouse     Aug 2006 3·52·79 Posts What are x and y? (Remember: when you're asking for help you need to be specific!)
 2010-11-12, 20:01 #42 science_man_88     "Forget I exist" Jul 2009 Dumbassville 26·131 Posts for example 2047 = 23*89 2+4+7=4 mod 9 2+3+8+9 = 4 mod 9 5+8 = 4 mod 9 so the sumdigits for each multiplier 2kp+1 summed together gives the same as the sumdigits for 2^p+1.
 2010-11-12, 20:03 #43 CRGreathouse     Aug 2006 3×52×79 Posts So... what are x and y?
2010-11-12, 20:03   #44
science_man_88

"Forget I exist"
Jul 2009
Dumbassville

20C016 Posts

Quote:
 Originally Posted by CRGreathouse So... what are x and y?
23 and 89 in this case.

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