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Old 2009-09-01, 20:22   #23
mart_r
 
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Dec 2008
you know...around...

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666*777=517482
and
666/777=.857142...

49899989999999^4=6200144830041037000103201165060058012000400400040000001
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Old 2009-09-26, 04:45   #24
Damian
 
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1+2+3+4+5+...+\infty = -\frac{1}{12}
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Old 2009-09-26, 06:16   #25
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\mbox{The Area of an Ellipse is }\pi*a*b
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Old 2011-10-09, 18:38   #26
Dubslow
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Jun 2011
40<A<43 -89<O<-88

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<br />
cosh(ix) = cos(x)<br />
\\cos(ix) = cosh(x)<br />
\\sinh(ix) = i sin(x)<br />
\\sin(ix) = i sinh(x)<br />

btw I can't TeX
It took me ten minutes of furious work to get them on separate lines

Last fiddled with by Dubslow on 2011-10-09 at 18:48
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Old 2011-10-09, 19:56   #27
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G_6(\frac{a+i}{N})=0 iff a^2\equiv-1\quad\pmod{N} where i^2=-1 and [TEX]G_6(\tau)=\sum_{(m,n)\in\mathbb{Z}^2\backslash\{(0,0)\}}\frac{1}{(m+n\tau)^6}[/TEX]
(N must be representable as N=c^2+d^2 with c, d coprime integers)

Last fiddled with by ccorn on 2011-10-09 at 20:45 Reason: added condition on N
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Old 2011-10-09, 22:22   #28
EdH
 
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-1 = -1

\frac{1}{-1} = \frac{-1}{1}

\sqrt{\frac{1}{-1}} =\sqrt{ \frac{-1}{1}}

\frac{\sqrt{1}}{\sqrt{-1}} =\frac{\sqrt{ -1}}{\sqrt{1}}

(\sqrt{1})^2 = (\sqrt{-1})^2

1 = -1
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Old 2011-10-10, 09:34   #29
xilman
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Down not across

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i^2 = j^2 = k^2 = ijk = -1
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