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 2007-04-21, 17:09 #1 mfgoode Bronze Medalist     Jan 2004 Mumbai,India 22·33·19 Posts Simple Arithmetic! Is this equation correct ? 2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ? Mally
 2007-04-22, 04:31 #2 mfgoode Bronze Medalist     Jan 2004 Mumbai,India 22·33·19 Posts Wrong local time! Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later! Something wrong with the software? The next post on has been put later than my post and hence given preference. Mally P.S. it has been immediately corrected during writing of this reply. Last fiddled with by mfgoode on 2007-04-22 at 04:33
2007-04-22, 04:53   #3
m_f_h

Feb 2007

24×33 Posts

Quote:
 Originally Posted by mfgoode Is this equation correct ? 2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ? Mally
It depends on what the "." and "*" mean (in regular expressions (regexp) the former represent an arbitrary character, in DOS command lines the latter represent an arbitrary sequence of characters ;
finally [ ] might be the "Gaussklammer"...

 2007-04-22, 08:11 #4 retina Undefined     "The unspeakable one" Jun 2006 My evil lair 2×32×11×29 Posts One side is sqrt(2) larger than the other. Is that supposed to be a puzzle or just something you don't understand?
2007-04-22, 11:06   #5
victor

Oct 2005
Fribourg, Switzerlan

22·32·7 Posts

Quote:
 Originally Posted by mfgoode Is this equation correct ? 2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ? Mally

Yes it is.
If . and * mean multiplication, and sq, rt are variable.
2 x y (2/3) = x y 2 (2/3) ...

Last fiddled with by victor on 2007-04-22 at 11:06

 2007-04-22, 11:26 #6 S485122     Sep 2006 Brussels, Belgium 23×197 Posts If . and * are multiplication what is the meaning of the concatenation of the two in the first part of the first term : "2.*sq". In the formula I see a lot of (intentional ?) inconsistencies : "2." versus "2*", "rt" versus "rt." My first intention was asking what the ".", the "*" and "sq.rt" meant. But then I realised it could be the core of the riddle.
2007-04-22, 16:53   #7
Orgasmic Troll
Cranksta Rap Ayatollah

Jul 2003

641 Posts

Quote:
 Originally Posted by mfgoode Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later! Something wrong with the software? The next post on has been put later than my post and hence given preference. Mally P.S. it has been immediately corrected during writing of this reply.
.
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2007-04-23, 03:41   #8
mfgoode
Bronze Medalist

Jan 2004
Mumbai,India

40048 Posts
characters!

Quote:
 Originally Posted by m_f_h It depends on what the "." and "*" mean (in regular expressions (regexp) the former represent an arbitrary character, in DOS command lines the latter represent an arbitrary sequence of characters ; finally [ ] might be the "Gaussklammer"...
Sorry for the confusion.

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

means 2 multiplied by the square root of 2/3 = square root of 2 multiplied by 2/3. So in one side the 2 is outside the square root on the other 2 is inside the square root.

* is multiplication, []are brackets, Its not the Gaussklammer.
'.' is full stop.
It is not a riddle! Its just a maths curiosity which looks odd and that it is wrong but it is right.

Mally

2007-04-23, 03:46   #9
mfgoode
Bronze Medalist

Jan 2004
Mumbai,India

1000000001002 Posts

Quote:
 Originally Posted by Orgasmic Troll .
I had my launchcast radio on, on 'My Station' and believe it or not that guy on the keyboard was actually keeping in time to it. Amazing!

Mally

 2007-04-23, 05:26 #10 Orgasmic Troll Cranksta Rap Ayatollah     Jul 2003 641 Posts so you're claiming that $(2)( \sqrt{\frac{2}{3}}) = \sqrt{(2) (\frac{2}{3})}$? $(2)( \sqrt{\frac{2}{3}}) = \sqrt{(4) (\frac{2}{3})} \neq \sqrt{(2) (\frac{2}{3})}$
 2007-04-23, 08:38 #11 mfgoode Bronze Medalist     Jan 2004 Mumbai,India 22·33·19 Posts Yes. The version you have given is totally wrong Mally Last fiddled with by mfgoode on 2007-04-23 at 08:41

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