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 2021-12-18, 16:51 #1 mart_r     Dec 2008 you know...around... 11000011112 Posts TeX expression not right I hope this roughly qualifies as homework help. I've been spending an hour to get this one line into the TeXworks program: Code: \Bbb P(\xi_n=1)={1\over\log n} \mbox{ and } \Bbb P(\xi_n=0)=1-{1\over\log n} What I get is shown in the attachment. I was happy to have the left half of the expression finally work out correctly, but the right half is slowly driving me berserk. What am I doing wrong? Thanks in advance! Attached Thumbnails
 2021-12-18, 17:04 #2 kruoli     "Oliver" Sep 2017 Porta Westfalica, DE 26·17 Posts $$\Bbb P(\xi_n=1)={1\over\log n} \mbox{ and } \Bbb P(\xi_n=0)=1-{1\over\log n}$$ Hm... It is interpreted the way you want here. Have you tried: {\Bbb P}(\xi_n=1)={1\over\log n} \mbox{ and } {\Bbb P}(\xi_n=0)=1-{1\over\log n} $${\Bbb P}(\xi_n=1)={1\over\log n} \mbox{ and } {\Bbb P}(\xi_n=0)=1-{1\over\log n}$$
 2021-12-18, 18:08 #3 mart_r     Dec 2008 you know...around... 11000011112 Posts I know, it works outside of the program. But the trick with bracketing the "\Bbb P" part had the desired effect, now the outcome looks like it should. Thanks a lot!
 2021-12-18, 21:17 #4 kruoli     "Oliver" Sep 2017 Porta Westfalica, DE 26·17 Posts Some clarification for this: There are some TeX-commands that work like a function with one parameter (which will be the same if written as \x{y} or \x y), multiple parameters (as in \x{y}{z}...) and there are functions that work like a switch (meaning that using them will be applied to the whole current block). I'm leaving out optional parameters here and I might be simplifying things a lot.

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