20220618, 01:46  #1 
"Matthew Anderson"
Dec 2010
Oregon, USA
2247_{8} Posts 
Beal's conjecture prize
Hi again everybody,
Matt here with some exciting (old) news. The prize is US$1 million per problem. There were 7 unsolved (very) hard mathematics problems set out by the Clay Mathematics Institute around the year 2,000. One of them was (sort of) recently solved. Now, let's look at the Beal conjecture. It is a generalization of Fermat's last theorem. The Beal Conjecture is something like a^x + b^y = c^z where all variables are both positive and integers. Wow! What a problem. see wikipedia.org https://en.wikipedia.org/wiki/Millennium_Prize_Problems and https://en.wikipedia.org/wiki/Beal_conjecture This is the sort of problem that definitely takes collaboration. One person cannot (yet) do it alone. IMHO (In My Humble Opinion) Have a nice day. Matthew 
20220619, 19:03  #2  
Bamboozled!
"๐บ๐๐ท๐ท๐ญ"
May 2003
Down not across
2^{3}×3×5×97 Posts 
Beal's (Conjecture Prize)
Someone who wishes to remain anonymous has brought this to my attention, hence my careful parenthesization ot this post's title.
Quote:


20220619, 23:49  #3 
Random Account
Aug 2009
Not U. + S.A.
2^{3}×3^{2}×5×7 Posts 
This very much resembles something I saw in a trade school class: a^{2} + b^{2} = c^{2}. Pythagorean Theorem, to be exact. The resolution was c = Sqrt(a^{2} + b^{2}), if memory serves. The length of the hypotenuse of a right triangle. It was a long time ago.

20220620, 00:26  #4  
2^{2}·31·79 Posts 
Quote:
If history is any guide...Farey...Haros (who the hell is Haros?)..Euler..Pell (what was it that Pell did again?)..equitable attribution in mathematics..there's more than enough precedent to lay waste to any claims of "fair and appropriate" attribution. Might as well name a planet Pluto and expect that to stick.. 

20220620, 08:48  #5 
Bamboozled!
"๐บ๐๐ท๐ท๐ญ"
May 2003
Down not across
10110101111000_{2} Posts 
Why, in your professional opinion, do you think the Poincarรฉ conjecture is only "sort of" solved?

20220620, 16:05  #6 
Random Account
Aug 2009
Not U. + S.A.
2^{3}·3^{2}·5·7 Posts 
Someone here, with the ability, should write a program to do this, unless something already exists. There would need to be an ordered progression and not random numbers. The language platform would need to handle very large numbers. The only one I am familiar with can handle 64bit unsigned integer types, 0 to 18,446,744,073,709,551,615, (FFFF FFFF FFFF FFFF). This might be large enough, then again, it may not.

20220620, 16:41  #7  
Mar 2019
2·163 Posts 
Quote:


20220620, 17:23  #8 
"Mark"
Apr 2003
Between here and the
1101100101110_{2} Posts 
Just don't bring up Don Blazys's proof. He was a crackpot who could not accept that his proof had flaws. You can search the forum for our debates with him on his proof. He tried passing off his proof in many places and just assumed it was correct if nobody disagreed. It doesn't mean that anyone agreed...

20220620, 22:30  #11  
If I May
"Chris Halsall"
Sep 2002
Barbados
2B34_{16} Posts 
Quote:
In at least one case it has been well documented that if you're going to do an exhaustive search, it is best to use C. If not handcrafted assembly, tuned to each processor... 

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