Some Somewhat Easier n^i Sequences Available for Termination

[EdH]

In looking over the tables I'm seeing what I'll call stragglers that are within reach, although some are bordering on discomfort. 293^65, as mentioned, and 14536^38 fall into the comfortable straggler category, while 263^69 falls into the uncomfortable straggler category. I have started work on all three. They should complete their bases when terminated.

[gd_barnes]

Post #1 duplicated itself. The top part is correct. The bottom part is what it was like last night.

I find stragglers often. Most of the "random" terminations you see of mine is me running additional ECM on some decent looking sequences and they happen to crack. Often that's all that is needed to make it much easier to terminate.

[gd_barnes]

35^107, 44^94, and 59^93 terminate

[EdH]

Thanks for helping me keep post #1 straight. I figured the stragglers I mentioned were already ECM'd by you and deemed outside your reach, so I'm bringing them down to <140. I'll be tied up shortly, so I've queued the two mentioned and we can discuss further work later.

[gd_barnes]

306^64 terminates.

That completes base 306! Nice work, Ed, to bring that one down.

I just realized this. The 59^93 that I just terminated brought base 59 down to only 59^95 remaining. It's 166/138/5. ECM to only t35. That one you might consider. It's not often we get close like that by chance on bases between 50 and 100. With 100 exponents each, they get large in size. We've already done the largest two exponents on this one.

There's a good chance that 59^95 could be easier than your 263^69, which is 164/160/7. ECM is done to t40 on it. If the C160 doesn't crack in ECM, it would be tough.

[gd_barnes]

392^61 terminates

[EdH]

263^69 is now at 155/153, so I'll let it finish (<140) and add 59^95. After that, I'll probably pick out some more stragglers. I also want to change my scripts a bit, but I'm going to be busy with other stuff tomorrow, so I don't know if I'll queue more sequences or work on the scripts if I have time at all..

[gd_barnes]

28^112 and 277^63 terminate

293^65 terminated by Ed.

That completes base 293! Pretty good for a base that was just recently initialized.

I've been taking on some tougher tasks and working on some that are current size < 150 digits in case we decide to tackle that group. Both of the ones that I terminated here were in that group. Most of the rest are pretty tough for me. I'll take one more last look over the list of them and see if there are any more that I can tackle.

Originally Posted by EdH

263^69 is now at 155/153, so I'll let it finish (<140) and add 59^95. After that, I'll probably pick out some more stragglers. I also want to change my scripts a bit, but I'm going to be busy with other stuff tomorrow, so I don't know if I'll queue more sequences or work on the scripts if I have time at all..

Nice! It looks like a normal amount of ECM on that C160 at I-3 would have been just enough to find the P43. So that helped a lot. Since then, it looks like it wasn't too bad for you until the C153.

I'm curious if you'll encounter some tough C150+'s on 59^95.

[gd_barnes]

59^95, 263^69, 1152^52, and 14536^38 terminate

Thank you, Ed, for the great reductions!

This completes bases 59, 263, and 14536!!

Including earlier bases 293 and 306, that completes 5 bases in a single 24-hour period!!

[gd_barnes]

Edited the last post for a 5th base completion in 24 hours. Signing off now. :-)

[EdH]

I added a progress file to my scripts and it shows ending status for each step of a sequence. Here's 293^65:

293^65 (151/138)
293^65 (150/137)
293^65 (149/124)
293^65 (149/112)
293^65 (148/139)
293^65 (147/135)
293^65 (147/142)
293^65 (146/130)
293^65 (145/127)
293^65 (Prime)

And, here's 59^95:

59^95 (161/154)
59^95 (158/156)
59^95 (157/149)
59^95 (149/145)
59^95 (137/122)

So, it fell pretty quickly.

I did some closer inspection of the entire set of what we have currently and we have completed six bases:

251
263
293
306
14536
2147483647

I see you mentioned five in your previous posts as having been completed in 24 hours.

We have four bases with only one sequence remaining:

277^69: 166/120
9699690^24: 168/146
200560490130^14: 160/131
7420738134810^14: 182/161

We should do at least the 277^69 sequence, but I'm not sure the weight of the others in Jean-Luc's upcoming harvest. If he caps his harvest at a certain base, these could be above that. The last one could definitely be a pain to terminate.

OTOH, there were a lot more bases with two sequences left than I realized:

37^105: 163/138
37^107: 155/137

42^98: 159/133
42^100: 155/147

55^93: 157/152
55^99: 172/126

241^67: 154/138
241^69: 160/119

257^65: 150/139
257^69: 161/128

281^67: 156/121
281^69: 148/148

288^64: 158/132
288^65: 158/137

385^61: 158/140
385^65: 161/155

552^58: 154/139
552^60: 165/157

660^56: 152/150
660^60: 170/140

1184^52: 160/152
1184^54: 166/154

2310^48: 161/140
2310^50: 168/140

12496^38: 156/145
12496^40: 164/158

14264^38: 157/145
14264^40: 167/159

14316^38: 159/129
14316^40: 167/152

131071^33: 161/138
131071^35: 172/171

510510^28: 145/143
510510^30: 172/151

These probably cover a good range of difficulty. I would probably work smallest "term set" to largest, if we decide to complete them. But, I would also look at the small factors for some like, 281^69: 148/148 (which I may actually run sooner than others).

I was going to ask if you wanted to run the c120 for 277^69, but I see you've signed off, so I'll see where it heads. It could easily be a pain with 3 and 7 sitting in a small factors list of five.