20100105, 15:38  #1 
Jan 2008
France
2^{3}×67 Posts 
New Pi Computation Record

20100106, 13:19  #2 
May 2003
Belgium
2·139 Posts 
This makes me think about the 'You might be addicted to GIMPS if...' thread.
All the CPU time 'wasted' for 2 letters... P I . If it had been 3... P I E :) 
20100106, 13:56  #3 
Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
17×251 Posts 

20100106, 15:14  #4 
Mar 2004
381_{10} Posts 
I assume he calculated 2.7 trillion digits, but had to remove some due to rounding errors during computation. (It is necessary to keep the full precision from beginning)
In such situations i always compute some million digits more. Just in case someone asks: "And what is the 10000000001 digit?" 
20100106, 16:51  #5  
Noodles
"Mr. Tuch"
Dec 2007
Chennai, India
3×419 Posts 
Quote:
Last fiddled with by Raman on 20100106 at 16:51 

20100106, 17:16  #6  
Sep 2006
Brussels, Belgium
2^{2}×3×7×19 Posts 
Quote:
Jacob 

20100106, 17:27  #7  
(loop (#_fork))
Feb 2006
Cambridge, England
1100010110011_{2} Posts 
Quote:
http://www.hpcs.cs.tsukuba.ac.jp/~daisuke/pi.html (yes, that page describes an earlier computation to 2.5e12 digits) there are thirteen consecutive eights. You could download http://gmplib.org/piwithgmp.html and compute a billion digits for yourself, which certainly will get you the first occurrence of 7{7} at index 3346228 and 8{8} at index 46663520; not sure about 9{9}, whose index is >2e8, unless you have access to a computer with 32GB of memory. http://mathworld.wolfram.com/PiDigits.html may also be of interest. 

20100106, 20:12  #9 
Mar 2004
3·127 Posts 
1.25 trillion digits:
repdigits of length 12 http://www.supercomputing.org/pidecimal_current.html 777777777777 : from 368,299,898,266th of pi 999999999999 : from 897,831,316,556th of pi 111111111111 : from 1,041,032,609,981th of pi 888888888888 : from 1,141,385,905,180th of pi 666666666666 : from 1,221,587,715,177th of pi Repdigits of length 9 appear 1000 times more often. That means every digit appears 2700 times in a group of 9. (a group of 10 counts lnke 2 groups of 9) 
20100106, 20:25  #10 
Dec 2008
you know...around...
2^{5}×19 Posts 
I believe the question for 9 consecutive 9's can be answered here:
http://www.research.att.com/~njas/sequences/A048940: Position 564665206. 
20100107, 14:32  #11 
Mar 2004
575_{8} Posts 
Actually all sequences about consecutive digits of pi could be extended to 12 or 13 with the new calculation.
http://mathworld.wolfram.com/PiDigits.html 
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