20220715, 08:38  #34  
"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
7^{2}·73 Posts 
Quote:
Also other sequences like https://oeis.org/A000110, https://oeis.org/A000111, https://oeis.org/A000670, https://oeis.org/A001006? Last fiddled with by sweety439 on 20220715 at 08:38 

20220715, 09:23  #35  
Apr 2020
1527_{8} Posts 
Quote:
Last fiddled with by charybdis on 20220715 at 09:25 

20220715, 17:27  #36  
Jul 2003
So Cal
3·823 Posts 
Quote:


20220716, 07:01  #37 
Sep 2002
Database er0rr
11·389 Posts 
Using the following function to reverse the digits of number of partitions:
Code:
revnumbpart(n)=V=digits(numbpart(n));a=0;for(k=1,#V,a+=V[k]*10^(k1));a; Code:
for(n=1,1000,if(ispseudoprime(revnumbpart(n)),print([n]))) [2] [3] [4] [5] [6] [9] [13] [23] [27] [34] [47] [100] [141] [185] [186] [187] [236] [241] [255] [271] [306] [310] [318] [378] [441] [481] [510] [532] [549] [661] [769] [868] [895] [931] Last fiddled with by paulunderwood on 20220716 at 07:07 
20220717, 08:07  #38 
Sep 2002
Database er0rr
11×389 Posts 

20220721, 11:51  #39 
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2^{4}·3^{3}·23 Posts 
p(19439060) and p(19439060)+4 are cousin primes.
Work in progress: A355956 = 3, 5, 6, 13, 36, 157, 302, 546, 2502, 2732, 19439060, ... 
20220802, 20:45  #40 
Jul 2003
So Cal
4645_{8} Posts 
To no one's surprise, p(1000007396) is prime.
Last fiddled with by frmky on 20220802 at 20:45 
20220802, 22:59  #41  
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2^{4}·3^{3}·23 Posts 
Quote:
But... but.. if you sum up 1000007396's digits you will get 26. Therefore, the digital root is 8. If you take the digital root of p(1000007396) you will also get 8. And if you take the digital root of numeric square root of p(1000007396) you will also get 8. And Zawahiri's name has 8 letters. This is not a coincidence! There is a deep conspiracy. {parody /} ...and half of it is not even true 

20220802, 23:31  #42  
Sep 2002
Database er0rr
11×389 Posts 
Quote:


20220804, 01:37  #44 
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2^{4}×3^{3}×23 Posts 

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