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Old 2020-02-13, 12:52   #1
enzocreti
 
Mar 2018

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Default Constellations of multiples of 3 in this sequence

47, 51, 52, 59, 68, 70, 75, 79, 90, 94,95, 102, 111


This is a sequence of numbers that reduced mod 41 are powers.


Are there infinitely many primes in this sequence?

Last fiddled with by enzocreti on 2020-02-13 at 14:00
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Old 2020-02-14, 07:15   #2
LaurV
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Jun 2011
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Quote:
Originally Posted by enzocreti View Post
47, 51, 52, 59, 68, 70, 75, 79, 90, 94,95, 102, 111
This is a sequence of numbers that reduced mod 41 are powers.
Are there infinitely many primes in this sequence?
Really? Whose power is 6? (i.e. .47 (mod 41))
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Old 2020-02-14, 12:20   #3
sweety439
 
Nov 2016

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Quote:
Originally Posted by enzocreti View Post
47, 51, 52, 59, 68, 70, 75, 79, 90, 94,95, 102, 111


This is a sequence of numbers that reduced mod 41 are powers.


Are there infinitely many primes in this sequence?
Of course!!! By Dirichlet's theorem on arithmetic progressions, there are infinitely many primes = 4 mod 41, thus there are infinitely many such primes.
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Old 2020-02-14, 12:21   #4
sweety439
 
Nov 2016

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Quote:
Originally Posted by enzocreti View Post
47, 51, 52, 59, 68, 70, 75, 79, 90, 94,95, 102, 111


This is a sequence of numbers that reduced mod 41 are powers.


Are there infinitely many primes in this sequence?
Wait!!! 47%41 = 6, and 6 is not perfect power....
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