20101113, 04:41  #56  
Aug 2006
13533_{8} Posts 
Quote:
Alternately, can you phrase his request unambiguously? If so I may be able to help. As it stands I have a few guesses as to where he might be going, but no firm ideas and certainly not a complete understanding. 

20101113, 05:05  #57 
May 2010
Prime hunting commission.
2^{4}·3·5·7 Posts 
Unambiguously? I think that may be an oxymoron.

20101113, 13:27  #58 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
I was saying that numbers of a specific sumdigits like 2 can be found to be possible in one case of 5mod9*8mod9 = 4mod9 so 2*2mod9 =4mod9 + 1 =5 so k=1 is an answer for a 5mod9 if we look for 8mod9 8*2mod9+1= 8mod9 so k=4 is a possibility in this case it works for 11 which is sumdigits(x)=2
Last fiddled with by science_man_88 on 20101113 at 14:12 
20101113, 14:10  #59 
Aug 2006
3×1,993 Posts 

20101113, 15:01  #60 
May 2010
Prime hunting commission.
2^{4}×3×5×7 Posts 

20101113, 15:09  #61 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 

20101113, 18:15  #62 
Aug 2006
175B_{16} Posts 

20101113, 18:21  #63 
May 2010
Prime hunting commission.
1680_{10} Posts 

20101113, 21:31  #64 
Aug 2006
3×1,993 Posts 

20101113, 22:49  #65 
"Forget I exist"
Jul 2009
Dumbassville
2^{6}×131 Posts 
does anyone else care what I'm talking about ?

20101114, 03:53  #66 
Aug 2006
175B_{16} Posts 
I can't tell if I care, because I can't understand you. The above flurry of posts was an attempt to get someone, perhaps Pi, to translate.
If you were more clear and explicit this wouldn't be needed, but that's life. You may be unable to write that way, or you may be unwilling to put in the effort. In the former case, that's a pity; you may have an interesting idea that no one will be able to get at. In the latter, don't expect others to do the work of extracting the information for you! Last fiddled with by CRGreathouse on 20101114 at 03:54 
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