20171228, 13:30  #67 
Oct 2005
Italy
3·113 Posts 
I try with M77324641

20171228, 13:37  #68 
Nov 2017
United Kingdom
13 Posts 
I thought the residue would be a string of zeroes for a prime. None of Jon's residue are such. So I suppose it's been removed from public record.

20171228, 13:40  #69 
Oct 2005
Italy
3·113 Posts 
If i remember correctly, the server writes a "masked" residue for a probable prime.
Last fiddled with by pacionet on 20171228 at 13:40 
20171228, 13:43  #70 
Serpentine Vermin Jar
Jul 2014
37×89 Posts 
Woohoo!
Just finished my doublecheck:
Mxxxxxxxx is prime! Looks like we have a winner, but my run was using the same Prime95 as the first result and I don't know if George will want to wait for the pending cudalucas check before making the exponent public. Traditionally I think that was the process. I saved the interim partial residues every 1M iterations (starting at 36M since I forgot at first) so we'll be comparing the cudalucas run along the way. But...yeah, the "Boxing Day Prime" looks good! 
20171228, 13:45  #71  
Oct 2005
Italy
3·113 Posts 
Quote:
Come on. :) 

20171228, 13:49  #72 
"Brian"
Jul 2007
The Netherlands
7·467 Posts 
I didn't believe GIMPS would ever find another one.
We know the exponent is above 36 million now. There I was thinking it might have been the result of a triple check of a mistakenly verified test from years and year ago. 
20171228, 13:54  #73 
"/X\(‘‘)/X\"
Jan 2013
5563_{8} Posts 

20171228, 13:56  #74 
Oct 2005
Italy
3·113 Posts 
I hope this forum will be the first to know the newly discovered prime! Come on!

20171228, 14:08  #75 
"/X\(‘‘)/X\"
Jan 2013
3×977 Posts 
Well we already knew that from earlier posted information. Ernst posted it would take at 72 hours to complete a run at 4 ms/iter, meaning it would be at least around 64 million.
Last fiddled with by Mark Rose on 20171228 at 14:08 
20171228, 14:13  #76 
Oct 2005
Italy
339_{10} Posts 
I found Madpoo test, the prime could be M64764893 :) which seems have 3 LL (1 failed e 2 OK)
MadPoo Manual testing 64764893 C 20171228 13:29 1.8 163.7113 7B56C023189FB494 rudimeier vinaka 64764893 C 20171226 14:35 12.6 157.0998 7B56C023189FB494 Is it? Last fiddled with by pacionet on 20171228 at 14:21 
20171228, 14:29  #77 
"Carlos Pinho"
Oct 2011
Milton Keynes, UK
11427_{8} Posts 
Maybe a decoy?

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