20201221, 22:21  #1134 
Nov 2016
2^{2}·3·5·47 Posts 
Riesel base 137
Code:
1,11 2,2 3,27 4,1 5,12 6,1 7,1 8,2 9,(partial algebra factors) 10,5 11,0 12,2 13,0 14,4 15,0 16,231 All k where k = m^2 and m = = 3 or 5 mod 8: for even n let k = m^2 and let n = 2*q; factors to: (m*137^q  1) * (m*137^q + 1) odd n: factor of 2 This includes k = 9 k = 11, 13, 15 remain at n=2000 Last fiddled with by sweety439 on 20210225 at 22:38 
20201221, 22:24  #1135 
Nov 2016
2^{2}·3·5·47 Posts 
Riesel base 138
Code:
1,2 138,1 275,1 412,2 549,4 686,1 823,1 960,1 1097,6 1234,28 1371,1 1508,2 1645,1 1782,2 Only list k == 1 mod 137 since other k are already in CRUS no remain k with k == 1 mod 137, totally list of the remain k is {408, 688, 831, 1074, 1743}, all remain at n=300K, see CRUS Last fiddled with by sweety439 on 20210227 at 06:57 
20201221, 22:25  #1136 
Nov 2016
2^{2}×3×5×47 Posts 
Riesel base 139
Code:
1,163 2,1 3,114 4,(partial algebra factors) 5,1 All k where k = m^2 and m = = 2 or 3 mod 5: for even n let k = m^2 and let n = 2*q; factors to: (m*139^q  1) * (m*139^q + 1) odd n: factor of 5 This includes k = 4 Conjecture proven 
20201221, 22:26  #1137 
Nov 2016
101100000100_{2} Posts 
Riesel base 140
Code:
1,79 2,2 3,1 4,5 5,30 6,1 7,7 8,2 9,1 10,1 11,108 12,2 13,7 14,16 15,1 16,1 17,8 18,6 19,1 20,2 21,1 22,1 23,2 24,1 25,1 26,4 27,1 28,1 29,18 30,2 31,1 32,16 33,12 34,1 35,6 36,1 37,1 38,448 39,2 40,9 41,8 42,1 43,3 44,2 45,1 Conjecture proven 
20201221, 23:59  #1138 
Nov 2016
2^{2}·3·5·47 Posts 
A (Sierpinski/Riesel) base b has 2cover if and only if b+1 is not prime or prime power

20201222, 00:00  #1139 
Nov 2016
2820_{10} Posts 
The formula for Sierpinski conjectures in CRUS is k*b^n+1
The formula for Riesel conjectures in CRUS is k*b^n1 The formula for Sierpinski conjectures in this project is (k*b^n+1)/gcd(k+1,b1) The formula for Riesel conjectures in this project is (k*b^n1)/gcd(k1,b1) 
20201222, 00:03  #1140 
Nov 2016
2^{2}·3·5·47 Posts 
The reason for (k=27 is excluded from S8 in this project) (k=4 is excluded from S16 in this project) (k=1 is excluded from R4 in this project) (k=1 is excluded from R8 in this project) (k=1 is excluded from R16 in this project) (k=1 is excluded from R36 in this project) (k=1 is excluded from R100 in this project) (k=1 is excluded from R128 in this project) is the same as (k=1 is excluded from R14 in CRUS) (k=1 is excluded from R18 in CRUS) (k=1 is excluded from R20 in CRUS) (k=1 is excluded from R24 in CRUS) (k=1 is excluded from R30 in CRUS) (k=1 is excluded from R32 in CRUS) (k=1 is excluded from R38 in CRUS) (k=1 is excluded from R42 in CRUS)

20201222, 00:05  #1141 
Nov 2016
2^{2}·3·5·47 Posts 
Riesel base 141
searched to n=2000, see the text file for the status, 0 if no (probable) prime found for this k
CK=285 Only k = 201 remain at n=2000 Last fiddled with by sweety439 on 20201222 at 00:19 
20201222, 00:13  #1142 
Nov 2016
2^{2}×3×5×47 Posts 
Riesel base 142
Code:
1,1231 2,1 3,26 4,3 5,1 6,3 7,1 8,7 9,1 10,2 11,14 Conjecture proven 
20201222, 00:14  #1143 
Nov 2016
2^{2}·3·5·47 Posts 
Riesel base 143
Code:
1,3 2,2 3,16 4,1 Conjecture proven 
20201222, 00:17  #1144 
Nov 2016
2^{2}×3×5×47 Posts 
Riesel base 144
Code:
1,(full algebra factors) 2,24 3,1 4,(full algebra factors) 5,1 6,1 7,5 8,1 9,(full algebra factors) 10,1 11,1 12,1 13,1 14,4 15,10 16,(full algebra factors) 17,1 18,1 19,4 20,1 21,1 22,1 23,134 24,2 25,(full algebra factors) 26,5 27,2 28,2 29,4 30,519 31,1 32,3 33,1 34,8 35,1 36,(full algebra factors) 37,3 38,1 39,964 40,1 41,1 42,1 43,2 44,6 45,3 46,97 47,2 48,1 49,(full algebra factors) 50,2 51,3 52,1 53,1 54,8 55,1 56,1 57,20 58,35 All k = m^2 for all n; factors to: (m*12^n  1) * (m*12^n + 1) This includes k = 1, 4, 9, 16, 25, 36, 49 Conjecture proven 
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