20150817, 17:21  #166  
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2^{5}·3·101 Posts 
Quote:
For starters, 10000, 20000, 30000 are listed twice; CK=41121 is listed as "remain"ing k. So it is already 827, not 828. There are also some differences of squares, cubes and seventh powers. P.S. 9216*708^n1 = (96*708^h1)*(96*708^h+1), with h=n/2, for even n; and divisible by 709 for odd n. Last fiddled with by Batalov on 20150817 at 19:25 

20150818, 00:28  #167 
"Mark"
Apr 2003
Between here and the
13·503 Posts 
Any ideas for having srbsieve autocompute the sieve depth?

20150818, 04:24  #168 
"Curtis"
Feb 2005
Riverside, CA
142C_{16} Posts 
The time spent sieving should be in the vicinity of 5% of the time it will take to test the entire file for primality. At very low exponents, this might be better set to 10%.
If there's a way to estimate how long it would take the PFGW the whole file (perhaps number of entries in the sieve multiplied by the time it takes to PFGW a candidate at the midpoint of the exponents), multiplying that by 10% and stopping srsieve at that time (rather than depth) should work. Of course, sieving reduces the number of tests in the sieve, and I have no idea what the right way to compensate for that is. Perhaps sieve to 100*maxn^2 (pulled from my &^%*), count the number of items in the sieve, then do this calculation? That won't be ideal for bases like R3 that lose a bunch of k's to primes, as those sieve files have most of their tests run well below the midpoint of the exponent range. But, it still prevents cases like my first couple tries at using srbsieve, where I ended up having it sieve for longer than it took the resulting file to PFGW completely. If one wanted to allow tinkering, one could make the 10% a setting in the .ini, so users can adjust the relative time spent in sieve; this allows stuff like R3 to run at 7%, or even lower, to compensate for the high frequency of primed k's. Edit much simpler is to find time to test a midpointexponent candidate, and sieve until time per factor equals that time. I think srsieve has that option as a flag? Last fiddled with by VBCurtis on 20150818 at 04:40 
20150818, 06:04  #169  
Jun 2008
Wollongong, .au
183_{10} Posts 
Quote:
Code:
S stoprate X Stop when it takes X seconds to eliminate a candidate. Last fiddled with by paleseptember on 20150818 at 06:06 

20150818, 11:00  #170 
Dec 2011
After milion nines:)
2723_{8} Posts 
And let someone who knows how Linux works help that Rogue compile srbsieve for Linux ( 64 bit)
I got testing S 810. On one machine it will be done at aprox ten days: on three will be done in 3.3 days :) So anyone? 
20150818, 11:22  #171 
Jul 2003
614_{10} Posts 

20150818, 13:04  #172 
Romulan Interpreter
"name field"
Jun 2011
Thailand
10011010010110_{2} Posts 
then use a higher X

20150818, 13:38  #173 
Jul 2003
614_{10} Posts 
do you know the real load of the machine ?
(an example: if the load is high you need to set S 30 and if the load is low to medium you need to set S 10 or so ...) p=xxx? would be better but who knows how to set it correct for each base and exponent ? 
20150818, 13:41  #174 
"Mark"
Apr 2003
Between here and the
13·503 Posts 
Code:
S stoprate X Stop when it takes X seconds to eliminate a candidate. 
20150818, 15:06  #175 
"Mark"
Apr 2003
Between here and the
13×503 Posts 
I cannot compile for linux as I do not have a linux machine. I have already explained earlier in this thread how to compile for linux. All you should need is the GNU Compiler Chain (gcc).

20150818, 15:48  #176 
"Curtis"
Feb 2005
Riverside, CA
2^{2}·1,291 Posts 
If the target time were found on the same machine with the same load, it would not matter how many tasks were running, as the result would still be "sieve until PFGW is faster on an avg candidate."

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