20200804, 20:16  #23  
May 2017
ITALY
194_{16} Posts 
Quote:
Let N=(4*b+2)^2(2*a1)^2=p*q > p=(4*b+2(2*a1)) and q=(4*b+2+(2*a1)) >p+q=8*b+4 > qp=4*a2 Let H=2*((3*N1)/81)/3+1 Let 18*(H*(H1)+H1)=A , A/144=C Let X=C/((H1)/2) & Y=C/((H+1)/2) then X+(a2)*21=b*(b+1) , N=(4*b+2)^2(2*a1)^2 or X+(a2)*21=b*(b+1) , N=(4*b+2)^2(2*a1)^2 game over 

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