20200523, 11:02  #1 
May 2020
5 Posts 
I think (wish) I find a new prime number record
hello i'm new to the forum and i discovered a new prime number how do i claim the reward?

20200523, 11:41  #2  
Undefined
"The unspeakable one"
Jun 2006
My evil lair
1606_{16} Posts 
Quote:
You won't get anything unless you show us your number is both large enough and is prime. Last fiddled with by retina on 20200523 at 11:43 

20200523, 11:48  #3 
May 2020
5_{8} Posts 
Descobri um número primo maior que o atual
2^102589933:sorriso: já mandei a reedificação
MODERATOR NOTE: Moved from "Mersenne prime in a Cunningham chain" thread. Note on current status: (assuming poster meant 2^102589933  1) Exponent status, No factors below 2^{74} Last fiddled with by Dr Sardonicus on 20200523 at 12:12 Reason: Note that post was moved; current info 
20200523, 11:55  #4 
"Carlos Pinho"
Oct 2011
Milton Keynes, UK
3×1,549 Posts 
Submit it here please: https://primes.utm.edu/primes/

20200523, 11:59  #5 
May 2020
101_{2} Posts 
This is the number
This is the number 2^102589933

20200523, 13:34  #6 
Romulan Interpreter
Jun 2011
Thailand
10000110111100_{2} Posts 

20200523, 13:56  #7 
"TF79LL86GIMPS96gpu17"
Mar 2017
US midwest
2^{3}×3^{2}×59 Posts 
That number is composite (not prime) by definition. b^{a} for b>1, a>1, a and b integer, is composite; b is a factor. This may win the prize for most obviously NOT prime (which is public embarrassment). It has one prime factor and over a hundred million distinct composite factors 2^{1}, 2^{2}, 2^{3}, ..., 2^{102589932}.
https://www.mersenneforum.org/showpo...65&postcount=3 It also happens to have a superficial relationship to the largest known Mersenne prime, 2^{82589933}1, whose exponent is 20M less. See also, for the perfect record of predicting large primes,by various means, https://www.mersenneforum.org/showpo...04&postcount=5 Possibilities, more likely first: Inaccurate post lacking +c, trolling, combination, computation error, something else, new prime discovery. In the very unlikely event that it's a Mersenne prime discovery, verification should have quietly occurred without posting an exponent, then announcement via MRI Inc. press release. https://www.mersenneforum.org/showpo...5&postcount=14 Last fiddled with by kriesel on 20200523 at 14:27 
20200523, 14:15  #8  
Sep 2002
Database er0rr
110100001011_{2} Posts 
Quote:


20200523, 14:28  #9  
"TF79LL86GIMPS96gpu17"
Mar 2017
US midwest
2^{3}×3^{2}×59 Posts 
Quote:
Maybe he meant a Fermat number. That claim would be safe from computational attack for a while. As stated in his post, a large power of two being prime, it's too absurd a claim to even bother including in the count in the "dubious claims" list behind the stats in https://www.mersenneforum.org/showpo...04&postcount=5 There are few rhyming prime exponents surviving even cursory TF above M82589933. 102589933 NF 74, further TF assigned to gpu72, P1 underway 112589933 small factor 222589933 small factor 232589933 NF 71, go to 79 assigned, no p1 yet 2290000,68700000 312589933 small factors 532589933 smallish factor 612589933 smallish factor 642589933 NF 70, go to 84 assigned, no p1 yet 5740000,172200000 652589933 NF 71, go to 84 assigned, no p1 yet 5820000,174600000 672589933 smallish factors 702589933 small factors 892589933 smallish factor 912589933 smallish factor 952589933 small factors (up to 999M) The 3 other survivors are being addressed with TF and may get some P1 attention after. Last fiddled with by kriesel on 20200523 at 15:25 

20200523, 18:02  #10 
May 2020
5 Posts 
Prime Number
70237298350549551468899 á is congruent with 1 (mod 4) and no cofactor is also known; therefore, there may still be a chance that 2 ^ 702372983505495514688991 is prime. This is just an example that I am taking into account.

20200523, 18:02  #11 
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
2·3^{2}·7·67 Posts 
What software did you use to test it?
If you were using mprime or Prime95, email the save files to George Woltman. If you used mlucas, contact Ernst Meyer with your save files. Do you have any interim residues? Those would be helpful (we could have others test it and if there are mismatches, we can see which 2 of 3 agree.) 
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