20100309, 19:40  #1  
"Mark"
Apr 2003
Between here and the
3·5·419 Posts 
Factoring EM47
Quote:


20100309, 19:52  #2  
Aug 2004
New Zealand
2×3×37 Posts 
Quote:


20100309, 19:58  #3 
Just call me Henry
"David"
Sep 2007
Cambridge (GMT/BST)
5,857 Posts 

20100309, 20:03  #4 
Nov 2008
2·3^{3}·43 Posts 
Just to clarify:
EM44 has factor 107 EM45 has factor 127 EM46 has factor 3313 EM47 is this number: Code:
1103211021556224950320857474629136274403207171149379589714114723150386622499653804938278785515108572580176773848180740319473132010224746780126854078078147700083327285484886146503985210746878713815121432016326226877964286156464913770459306370172713035675031 Last fiddled with by 10metreh on 20100309 at 20:07 
20100309, 21:39  #5 
Aug 2006
3^{2}×5×7×19 Posts 
I'm searching for factors of the c256 up to 45 digits (~9700 curves at 11M, simultaneous with 4700 at 3M).
Last fiddled with by CRGreathouse on 20100309 at 21:46 
20100309, 22:04  #6 
Jul 2003
So Cal
2·3·347 Posts 
The convention seems to be that the number generated by the n'th term is EMn, and factoring EMn gives the (n+1)^{th} term of the sequence. That is, the first 43 terms were known. Their product plus one is referred to as EM43. The smallest prime factor of EM43 is the 44'th term of the sequence.

20100310, 05:44  #7 
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
9489_{10} Posts 

20100310, 19:03  #8 
Aug 2004
New Zealand
2·3·37 Posts 
Not that it is needed, but one more factor for the 46th stage:
Code:
46 127.6069700067.56020785082237742556947.c215 
20100310, 19:06  #9 
Aug 2006
3^{2}·5·7·19 Posts 

20100310, 19:46  #11 
Mar 2006
Germany
43×67 Posts 
ok, was a quick shot!
perhaps 'NFS@Home' better? PS: edited! Last fiddled with by kar_bon on 20100310 at 19:50 