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#45 |
Sep 2017
23×3 Posts |
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dear sir if you don t mind can you pm your skype id than i give you more exmpel..
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#46 |
Feb 2017
Nowhere
22·1,039 Posts |
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Curiously, the OP's original question was posted to a Wolfram Stackexchange chat room the day before it was posted to this august Forum.
The user zhk had identified the trouble as an overflow problem. I also found an old thread in this Forum with exactly the same kind of calculation as in this one. Major difference: When asked, the OP in that thread described precisely what he was trying to do and why: It's possible to calculate an unknown RSA modulus? |
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#47 |
Sep 2017
23·3 Posts |
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yes DR sir my calculating string same like this:http://www.mersenneforum.org/showthread.php?t=13524
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#48 | |
"Robert Gerbicz"
Oct 2005
Hungary
26248 Posts |
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Code:
m1^e==c1 mod N [1] m2^e==c2 mod N [2] And why would anybody solve this problem where the original message is KNOWN ![]() |
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#49 |
Feb 2017
Nowhere
103C16 Posts |
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We've repeatedly told the OP "The numbers are too big"
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#50 |
Sep 2009
1,973 Posts |
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Could it be done by calculating everything mod some suitable prime larger than N, eg 2^521-1 (assuming N is RSA512)? Or mod several smaller primes and applying the Chinese Remainder Theorem to recover N?
Chris |
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#51 |
Sep 2017
1816 Posts |
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Dear all.
my string same like this N modul recover.. |
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#52 |
"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
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#53 |
Sep 2017
2410 Posts |
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no body try to solve this issu overflow?
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#54 |
Sep 2002
Database er0rr
3,527 Posts |
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Arbitrary precision arithmetic is a solved problem.
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#55 |
Sep 2017
1816 Posts |
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dear sir,
your send link not solve the probleam its all ready solve like old exp-65537 5 digt but new exp-12 digit can it possibel with exp calculating start? |
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