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#1 |
Feb 2004
Sydney
7 Posts |
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Hello I am very new to this but to a person that is no mathamatician, when I look at the short representation of the large Mersenne Prime, I see a -1 at the end. Now if thats what you have to do to the actually number, subtract 1 to make it a prime them the above mentioned number is NOT A PRIME. I am probably illinformed and wrong with the calculations but thats what I did and then divided it with a certain number and found it to be divisible by it. Can anyone please enlighten me of what is right or wrong?
![]() I told you i was very new!(hehehahah) |
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#2 |
Aug 2002
2·3·53 Posts |
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The actual number is 2 to the 20996011 power minus 1.
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#3 |
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
24×3×227 Posts |
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Yes, it is (220996011)-1 which is about 6.5 million digits long. The number is not 220996011-1 (which is even), nor is it (2 X 20996011)-1, nor even 220996011-1.
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#4 | |
Feb 2004
Sydney
7 Posts |
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Last fiddled with by illman-q on 2004-02-28 at 04:20 |
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#5 |
Oct 2003
Australia, Brisbane
2×5×47 Posts |
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Well, then - what is the factor????
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#6 | |
Nov 2003
3×5×11 Posts |
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#7 | |
Dec 2003
Team China
3616 Posts |
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#8 | |
Aug 2002
Portland, OR USA
2×137 Posts |
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= 2(2^10483005-1)(2^10483005+1) = 2(2^3494335-1)(2^6988670 + 2^3494335 + 1)(2^3494335+1)(2^6988670 - 2^3494335 + 1) = ... hmm, my binomial expansion skills are a bit rusty ... anyway, his factor is in there, but I vote for '2' as well. |
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#9 |
Bemusing Prompter
"Danny"
Dec 2002
California
5×499 Posts |
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Sounds like fame-bait to me...
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#10 | |
Feb 2004
Sydney
1112 Posts |
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Last fiddled with by illman-q on 2004-03-02 at 03:00 |
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#11 |
Bemusing Prompter
"Danny"
Dec 2002
California
1001101111112 Posts |
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Oops, meant to say "flame-bait"...
Last fiddled with by ixfd64 on 2004-03-04 at 02:27 |
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