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#1 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
2×34×37 Posts |
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Every odd number is half of an even number.
Some even numbers are not double an odd number. Therefore there are more even numbers than odd numbers. ![]() |
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#2 |
Dec 2012
The Netherlands
158210 Posts |
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Now you understand why number theorists introduce fractional ideals.
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#3 | |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
176A16 Posts |
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I don't understand? ![]() |
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#4 |
Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
10,499 Posts |
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There is precisely one more even number than there are odd numbers.
If a number is odd, so is its negative. All other numbers are even. However the negative of zero is itself zero. Consequently, it does not have a negative counterpart and is the sole exception mentioned above. |
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#5 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
7×283 Posts |
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I know you are kidding (countable infinities having 1 to 1 relations and all) but I will bite.
For every Even number m.2^n for integers m & n where m is odd, there exists one distinct odd integer m^n sooooo they are equal. I am sure there are other equally invalid logics which will result in there being more odd numbers than even ones but can't think of any just yet. ETA scrap that that only is distinct off m is not a power. Last fiddled with by a1call on 2020-08-03 at 10:01 |
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#6 | |
Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
10,499 Posts |
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It should have read "There is precisely one fewer even numbers than there are odd numbers." The proof itself remains unchanged. ![]() Last fiddled with by xilman on 2020-08-03 at 10:17 |
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#7 | |
"Rashid Naimi"
Oct 2015
Remote to Here/There
7×283 Posts |
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For every Even number m^a*2^n for integers m, a & n where m is odd, there exists two distinct odd integer m^n-/+m^a, sooooo there are twice as many odd numbers as there are even ones. ![]() Counterexamples are likely/appreciated. ![]() |
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#8 |
"TF79LL86GIMPS96gpu17"
Mar 2017
US midwest
29×167 Posts |
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#9 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
2×34×37 Posts |
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#10 |
"Jeppe"
Jan 2016
Denmark
163 Posts |
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I do see some correct statements above. They should be moved out of this crackpot subforum, by someone. Am I being trolled? /JeppeSN
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#11 |
Random Account
Aug 2009
U.S.A.
32×199 Posts |
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All of this seems to make something very simple into something very complex. It is not. If you take them in pairs, (one of each type), the count will be the same for odds and evens, if the counting stops on an even.
(1,2)(3,4)(5,6)(7,8) and so on. |
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