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#1 |
6809 > 6502
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Aug 2003
101×103 Posts
255778 Posts |
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Make yourself a crank.
![]() Propose a method to predict primes (or at least a bunch of likely candidates). General philospophy (rules): it needs to be somehow mathematic in nature. Using various bases and graphic methods are encouraged. The real small M's can be excluded. If you need to drop one out of the middle to make your "method" work, do so silently, it makes it more fun to slip things by people. Ideally, it is based upon some characteristics of the exponent, or some odd aspect of the digits of the decimal expansion. Don't worry if your method works for only the MP's that you can test by hand. Stated exceptions to the rule are encouraged. Ambigous language and logic problems (the more obscur the better) earn style points. You get the idea. Have fun. |
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#2 |
Jan 2006
JHB, South Africa
157 Posts |
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M45 has been predicted!!! 56367431
There is a simple way to predict it. I'm currently trimming the 39 page proof down to 3 lines, so please be patient, it should be ready by 2023. Regards Patrick ps. 'Mersenne' is reflected as a spelling error in the editor??? June 29 You will have your M45 (sooner if I get a faster CPU)! Last fiddled with by Patrick123 on 2007-03-15 at 20:04 |
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#3 |
"Michael Kwok"
Mar 2006
1,213 Posts |
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I have found many NEW, EXCITING mersenne primes using an IMPROVED version of a FOOLPROOF theorem by Master Alex, troels munkner, and Dr. David John Hill, Jr.
This theorem was produced during SEVEN LONG YEARS of careful study, beginning with the time I was a graduate student in MIT. I have labelled it the "Kwok-Alex-Munkner-Hill theorem", and it is IMPORTANT enough to REVOLUTIONIZE cryptography. I have often posted the EXACT PROOF and PROGRAMS needed to carry out the theorem, but I cannot do so today. This is because the GREEDY NAZI's of the board, EWMAYER, XYZZY, and PRIME95, want to SILENCE my work and claim the EFF prizes for themselves. All I will say is that it is based on a simple consequence of number theory. It shows that ANY FRACTION will either terminate or repeat infinitely. If the numerator and denominator are PRIME, the result will be a number that repeats only after a very long number of digits. Example: 73/19 goes 3.842105... and THE SEQUENCE only repeats 20 digits later, when 842105... shows up again. However, when the numerator and denominator are COMPOSITE, the number will either terminate or repeat after a very short number of digits. Example: 68/15 goes 4.533333, and the number 3 repeats every time. Therefore, when a fraction is evaluated, the LONGER it takes for a SEQUENCE in it to REPEAT, the greater the chance of the numerator and denominator being PRIME. This forms the basis of this PROOF, and I challenge ANYONE to find a "FLAW" in this theorem. Using that, I developed a VERY FAST computer program to divide possible candidates into each other. It went M3000001/M3000000, M3000002/M3000000, and so on until M79300000/M3000000. After that, the denominator was incremented, and it went: M3000000/M3000001, M3000002/M3000001, and so on until M79300000/M3000001. I kept on doing this until M79300000/M79299999. After each division, my program checked for the NUMBER OF DIGITS it took until a string of digits started repeating itself. I will not disclose my program for fear that someone will STEAL my program, COPYRIGHT it, and PROFIT from it. I ran the program for a year, and I found that after M32582657, there will be ONLY TWO prime numbers below M79,300,000, the current limit of the GIMPS software. Those two numbers are M68394881 and M74560093. I hope this gets me maximum points on the crank index: http://primes.utm.edu/notes/crackpot.html |
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#4 |
Jun 2005
5658 Posts |
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The only PROBLEM with your INCONTESTABLE PROOF is the CRAPPY gimps software, one MUST agree.
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#5 |
Jan 2006
JHB, South Africa
2358 Posts |
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#6 |
Jan 2006
JHB, South Africa
157 Posts |
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If I had to post my proof here, as what it stands, Dr. Silverman's understanding of it will be equivalent to a child in kindergarden vs Mr, Spock from Star-Trek.
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#7 |
"Michael Kwok"
Mar 2006
1,213 Posts |
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#8 |
Jan 2006
JHB, South Africa
157 Posts |
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#9 |
"Jason Goatcher"
Mar 2005
3×7×167 Posts |
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First, I must say I got this idea from someone else, I forget who. I wouldn't refer to them as a crank, as the thread was more of a "check this out" sort of thing.
[crank]Since p-1 and p+1 are mysterious methods to most people, including myself, I suggest that the smoother a prime number after it's biggest p-1 or p+1 factor is removed, the more likely that it will be prime. I am working on a simple formula that, while it's not guaranteed to find ALL primes, will greatly facilitate the search, and will allow us to find numbers 2-3 times bigger then with the methods Prime95 is incorporating. As an example, look at the number 127. We already know that 2^127-1 is prime, but look at the p-1 and p+1 aspect of it. P-1 yields 2*3^2*7, not very interesting. But p+1(128) yields 2^7, which is about a smooth as you can get.[/crank] If anyone wants to expand on my method, feel free. Please note that if this method is found to have any merit at all, it is because I am a lucky bastard, and not because I have any outstanding skills. |
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#10 | |
Jan 2006
JHB, South Africa
157 Posts |
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#11 |
Jan 2006
JHB, South Africa
2358 Posts |
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Great News!!!!!
I have now managed to create an algorithm that will allow the Lucas-Lehmer test to be spread across a multitude of computers. This will effectively allow us to prove my M45 number in an extremely short period of time. What I require of you is to provide me with at least 7 non-adiabatic Quantum Computers for three micro-seconds (Please ensure that there is a decent anti-virus program installed, double check it for spy-ware!!!). The Quantum Computers must be at least n^3 qubits in size. Regards Patrick ps. This beats the pants off Shor's algorithm ![]() |
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