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#1 |
Feb 2020
Germany
23·7 Posts |
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I was just wondering if there is a named form of prime numbers which are generated by the formula k*sum(p)+/-1?
With sum(p) I mean the sum of all primes up to p, in similar fashion to the primorials k*n#+/-1? I did a google search and did not find an answer, maybe I used the wrong search parameters? Thanks in advance, hunson |
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#2 | |
"Rashid Naimi"
Oct 2015
Remote to Here/There
41×59 Posts |
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With your proposed formula you get much smaller integers N with no easy way of factoring N+1 or N-1. This would make them not very interesting for large provable primes. Just my 2 cents. Last fiddled with by a1call on 2023-02-05 at 20:57 |
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#3 | |
Jan 2021
California
2·7·41 Posts |
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#4 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
97316 Posts |
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These links might be useful:
https://en.wikipedia.org/wiki/Catego..._prime_numbers https://primes.utm.edu/glossary/page...83,(p)%3Dp%2B1. Last fiddled with by a1call on 2023-02-05 at 21:08 |
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#5 |
If I May
"Chris Halsall"
Sep 2002
Barbados
22×5×571 Posts |
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#6 | |
"Rashid Naimi"
Oct 2015
Remote to Here/There
41·59 Posts |
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#7 |
If I May
"Chris Halsall"
Sep 2002
Barbados
22·5·571 Posts |
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#8 |
Feb 2020
Germany
23×7 Posts |
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Thanks for all the (serious) answers ;)
@a1call: You are right, numbers of the form in question do not tent to grow very fast. They are most certainly not suitable for record primes and factoring is much more difficult. Thanks for the links, I will look into it. |
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#9 | |
Feb 2017
Nowhere
23·283 Posts |
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so Asymptotically, the sum divided by n2*log(n) has limit 1/2 as n increases without bound, but for small n the ratio is somewhat larger. |
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#10 |
Aug 2020
79*6581e-4;3*2539e-3
733 Posts |
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What might be more interesting is factoring these numbers. You could even get rid of the +1 and just do the sum of primes.
https://oeis.org/A007504 is the respective sequence. |
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#11 |
Feb 2020
Germany
23×7 Posts |
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Asking as a non mathematician, what is the interesting outcome from factoring the sum of primes or the suggested prime-form? What could be learned from that?
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